$From\ 2nd\ Newton\ Law\ resultuant\ force: \\\\\ F_R=m*a=5kg*3,6\frac{m}{s^2}=18N\\\\
F=32N\\\\
F_f- friction\ force\\\\
F_R=F-F_f\\\\
F_f=F-F_R=32N-18N=14N\\\\Friction\ force\ is\ equal\ to\ 14\ N.$

3 0

3 years ago

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A student has a sample of aluminum that has a mass of 27 g and a volume of 10cm3. What is the density of aluminum

Anestetic [448]

Answer:

270 g/cm^3

Explanation:

d = mv

d = 27 g × 10cm^3

d = 270 g/cm^3

6 0

3 years ago

A sample of air occupies 4.40 L when the pressure is 2.60 atm.

julia-pushkina [17]

Explanation:

Given that,

Initial volume, V₁ = 4.40 L

Initial pressure, P₁ = 2.6 atm

(a) Final pressure, P₂ = 6.2 atm

As per the relation,

$P_1V_1=P_2V_2\\\\V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{2.6\times 4.4}{6.2}\\\\V_2=1.84\ L$

(b) Again using the above relation,

$P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{2.6\times 4.4}{0.0290 }\\\\P_2=394.48\ atm$

Hence, this is the required ssolution.

8 0

2 years ago