Hydrogen gas is generated when acids come into contact with certain metals. When excess hydrochloric acid reacts with 2.2 g of (
1 answer:
To solve the problem it is necessary to apply the concepts related to Byle's Law and Avogadro's Law.
The ideal gas equation would help us find the final solution to the problem, defined by
Where,
T= Temperature of the gas
R = Universal as constant
n = number of moles
V = Volume
P = Pressure
For our case we have that the mass of Zn is 2.2g in moles would be
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We know that 1 mole of hydrogen gas is proceed by 1 mole of zinc and the result is , then Hydrogen can produce the same quantity,
Applying the previous equation we have that
Therefore the volume of hydrogen gas is collected is 0.829L
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Answer:
μsmín = 0.1
Explanation:
- There are three external forces acting on the riders, two in the vertical direction that oppose each other, the force due to gravity (which we call weight) and the friction force.
- This friction force has a maximum value, that can be written as follows:
where μs is the coefficient of static friction, and Fn is the normal force,
perpendicular to the wall and aiming to the center of rotation.
- This force is the only force acting in the horizontal direction, but, at the same time, is the force that keeps the riders rotating, which is the centripetal force.
- This force has the following general expression:
where ω is the angular velocity of the riders, and r the distance to the
center of rotation (the radius of the circle), and m the mass of the
riders.
Since Fc is actually Fn, we can replace the right side of (2) in (1), as
follows:
- When the riders are on the verge of sliding down, this force must be equal to the weight Fg, so we can write the following equation:
- (The coefficient of static friction is the minimum possible, due to any value less than it would cause the riders to slide down)
- Cancelling the masses on both sides of (4), we get:
- Prior to solve (5) we need to convert ω from rev/min to rad/sec, as follows:
- Replacing by the givens in (5), we can solve for μsmín, as follows: