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Rom4ik [11]
3 years ago
13

Assignments

Physics
1 answer:
sladkih [1.3K]3 years ago
4 0

Hello there!

I hope you and your family are staying safe and healthy during this unprecendented time.

A) What is the work done?

Answer: We need to use the formula

w=-F_f(d)

w=-(35)(20)

w=-700J

B) What is the work done on the cart by the gravitational force?  

Alright, we know that the gravitional force is perpendicular to the diplacement. Therefore, we gonna use the following formula:

w=Fdcos90

w=0

C) What is the work done on the cart by the shopper?

This is the easier part, since we already know that the work done by the shopper is the same as the work done by the friction force

W shopper + W friction = 0\\W shopper = W-friction \\W shopper = 700J

D) Find the force the shopper exerts, using energy considerations.

F_f+Fcos25=0\\-35+Fcos25=0\\F=38.6N

E) What is the total work done?

You just need to add them:

w=wshopper+wfriction\\w=0

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storchak [24]

Answer:

Explanation:

We shall take the help of vector form of displacement . Taking east as i and north as j

4.0m N = 4 j

7.5 m E = 7.5 i

6.8 m S = - 6.8 j

3.7 m E, = 3.7 i

3.6 m S = - 3.6 j

5.3 m W = - 5.3 i

3.7 m N, = 3.7 j

5.6 m W = - 5.6 i

4.4 m S = - 4.4 j

4.9 m W = -  4.9 i

Total displacement = 4j +7.5 i -6.8j+3.7i-3.6j-5.3i+3.7j-5.6i-4.4j-4.9i

= -4.6 i -7.1 j

magnitude of displacement = \sqrt{(4.6^2+7.1^2)}

= 8.46 m

Direction

Tanθ = 7.1/ 4.6

θ = 57⁰ south of west .

distance walked = 4+7.5 +6.8+3.7+3.6+5.3+3.7+5.6+4.4+4.9

= 49.5 m

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3 years ago
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A student pulls a cart across the floor with a force of 45 N. If the cart travels 10 m, how much work does the cart do on the st
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An electron is released from rest in a weak electric field given by vector E = -1.30 10-10 N/C ĵ. After the electron has travel
Murljashka [212]

Answer:

v =  6.45 10⁻³ m / s

Explanation:

Electric force is

               F = q E

Where q is the charge and E is the electric field

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                F- W = m a

               a = F / m - g

               a = q / m E  g

Let's calculate

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              a = 0.228 10² -9.8

              a=  13.0 m / s²

Now we can use kinematics, knowing that the resting parts electrons

              v² = v₀² + 2 a y

              v =√ (0 + 2 13.0 1.6 10⁻⁶)

            v =  6.45 10⁻³ m / s

4 0
3 years ago
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