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solniwko [45]
3 years ago
8

What is difference between dipole dipole interaction and hydrogen bonding ​

Chemistry
2 answers:
aalyn [17]3 years ago
8 0

Answer:

A dipole-dipole force is when the positive side of a polar molecule attracts the negative side of another polar molecule.

A hydrogen bond is a dipole-dipole force and is an attraction between a slightly positive hydrogen on one molecule and a slightly negative atom on another molecule.

Kipish [7]3 years ago
7 0

Answer:

Hydrogen bonds are dipole-dipole interactions in which at least one of the atoms involved is a hydrogen atom. Dipole-induced dipole bonds are those electric bonds that exist between a molecule with a permanent dipole moment and a molecule in which a temporary dipole moment has been induced.

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Answer:

\displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}

Explanation:

Volume of a cone:

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We have \displaystyle \frac{dV}{dt} = \frac{10 \ cm^3}{sec} and we want to find \displaystyle \frac{dh}{dt} \Biggr | _{h\ =\ 6}= \ ? when the height is 2 cm.

We can see in our equation for the volume of a cone that we have three variables: V, r, and h.

Since we only have dV/dt and dh/dt, we can rewrite the equation in terms of h only.

We are given that the height of the cone is 1/5 the radius at any given time, 1/5r, so we can write this as r = 5h.

Plug this value for r into the volume formula:

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Differentiate this equation with respect to time t.

  • \displaystyle \frac{dV}{dt}  =\frac{25}{3} \pi \ 3h^2 \ \frac{dh}{dt}
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Plug known values into the equation and solve for dh/dt.

  • \displaystyle 10 = 25 \pi (2)^2  \ \frac{dh}{dt}
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Divide both sides by 100π to solve for dh/dt.

  • \displaystyle \frac{10}{100 \pi} = \frac{dh}{dt}
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The height of the cone is increasing at a rate of 1/10π cm per second.

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