Answer:
0.0008 m
Explanation:
We are given that 0.080 cm
We have to convert 0.080 cm into meter
To find the value of 0.080 cm in meter we are using unitary method
We know that
100 cm =1 m
1 cm =
Therefore, 0.080 cm =
0.080 cm =
0.080 cm =
0.08cm=0.0008 m
Hence, the value of 0.080 cm is equal to 0.0008 meter .
Answer:
An atom of Al which has 13 protons and 10 electrons is Al cation (Al⁺³)
Explanation:
An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.
All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other.
For example,
Al atom has 13 protons and 13 electrons. The number of positive and negative charge is equal thus it will be neutral atom.
While the atom of Al which have 13 proton and 10 electron is not neutral. The positive charge is greater than negative by 3. Which means 3 electrons are lose by Al atom and form cation "Al⁺³".
Thus an atom of Al which has 13 protons and 10 electrons is Al cation (Al⁺³)
We have seasons on earth because of the way the earth is tilt on its axis. at a certain time in the year, the sun's rays reach certain parts of the globe more than others.
some places have 4 seasons because they are in the northern hemisphere, which is in the sweet spot of the sun's rays that give us each season. other places only have 1 or 2 because they are not in the northern hemisphere.
Moles of solute for both a and b are the same = 1 mol
<h3>Further explanation</h3>
Given
a 500 cm³ of solution, of concentration 2 mol/dm³
b 2 litres of solution, of concentration 0.5 mol/dm³
Required
moles of solute
Solution
Molarity shows the number of moles of solute in every 1 liter of solution or mmol in each ml of solution
Can be formulated :

a.
V = 500 cm³ = 0.5 L
M = 2 mol/L
n=moles = M x V
n = 2 mol/L x 0.5 L
n = 1 mol
b.
V = 2 L
M = 0.5 mol/L
n=moles = M x V
n = 0.5 mol/L x 2 L
n = 1 mol