Question

If 9.6 X 1021 molecules of hydrogen are reacted with excess nitrogen, how many liters of ammonia can be produced at STP?

Answer 1

The volume of NH₃ produced at STP : 0.237 L

Further explanation

Reaction

N₂ + 3H₂ → 2NH₃

1 mol = 6.02 x 10²³ particles

9.6 X 10²¹ molecules of Hydrogen, mol :

$\tt \dfrac{9.61\times 10^{21}}{6.02\times 10^{23}}=1.596\times 10^{-2}~moles$

mol H₂ : mol NH₃ = 3 : 2

mol NH₃ :

$\tt \dfrac{2}{3}\times 1.596\times 10^{-2}=0.0106$

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.

The volume of NH₃ :

$\tt 0.0106\times 22.4=0.237~L$