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Murrr4er [49]
2 years ago
12

How would you expect earthworms to respond to any strong chemical odor? WILL GIVE BRAINLIEST IF RIGHT!!!

Physics
2 answers:
omeli [17]2 years ago
6 0

Answer:

if the earthworm smells the strong odor it will back away from it because it thinks it's a sign of danger.

Setler [38]2 years ago
4 0

Answer:

<em><u>Hypothesis #2 If an earthworm is exposed to a strong odor, then it will back away from the odor because it will think that the odor is a sign of danger. ... Second, you will test earthworms' response to dry conditions by providing both a dry surface and a moist surface for the earthworms to crawl on.</u></em>

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Gravity on Earth is 9.8 m/s2, and gravity on Mars is 3.7 m/s2.
antiseptic1488 [7]
W = mg

Weight on Earth = 50 x 9.8
                          = 490 N

Weight on Mars = 50 x 3.7
                          = 185 N 
8 0
3 years ago
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snow_lady [41]
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Define SI unit of measurement.​
ivanzaharov [21]

Answer:

the group of units suggested by the international convention of scientists in 1960 AD to make similarties in meseurment all over the world is called SI units

3 0
2 years ago
What speed would a fly with a mass of 0.55g need in order to have a kinetic energy of 7.6 •10^4 j?
masya89 [10]

Answer:

16613 m/s

Explanation:

Given that

mass of the fly, m = 0.55 g = 0.55*10^-3 kg

Kinetic Energy of the fly, E = 7.6*10^4 J

Speed of the fly, v = ? m/s

We know that the Kinetic Energy is that energy that an object, in this case, the fly, possesses due to its motion.

The Kinetic Energy, KE of any object is represented by the formula

KE = 1/2 * m * v²

If we substitute the values in the relation, we have,

7.6*10^4 = 1/2 * 0.55*10^-3 * v²

v² = (15.2*10^4) / 0.55*10^-3

v² = 2.76*10^8

v = √2.76*10^8

v = 16613 m/s

Thus, the fly would need a speed of 16.6 km/s in order to have a Kinetic Energy of 7.6*10^4 J

7 0
3 years ago
A planet orbits a sun in a clockwise elliptical orbit as shown in the diagram below
STatiana [176]

Answer:

Greatest gravitational energy is at "C".

The planet has to do work "against" the field to get to "C".

Also, if m v R (angular momentum) is constant then as R increases v must decrease for this term to be constant and KE = 1/2 M v^2  must decrease also to get to point C.

3 0
2 years ago
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