All categories

3 years ago

How would you expect earthworms to respond to any strong chemical odor? WILL GIVE BRAINLIEST IF RIGHT!!!

Physics

2 answers:

omeli [17]3 years ago

6 0

Answer:

if the earthworm smells the strong odor it will back away from it because it thinks it's a sign of danger.

Setler [38]3 years ago

4 0

Answer:

<em><u>Hypothesis #2 If an earthworm is exposed to a strong odor, then it will back away from the odor because it will think that the odor is a sign of danger. ... Second, you will test earthworms' response to dry conditions by providing both a dry surface and a moist surface for the earthworms to crawl on.</u></em>

You might be interested in

With an average surface temperature of about 737 K, _______ is the hottest planet.

givi [52]

With an average surface temperature of about 737 K, Venus is the hottest planet.

While Mercury is closest to the sun, it has gaseous molecules that protect it. Venus is the second closest planet to the sun, and is the hottest planet.

3 0

3 years ago

Read 2 more answers

What is the distance between a 900 kg compact car and a 1600 kg pickup truck if the gravitational force between them is about 0.

elena-14-01-66 [18.8K]

Answer:

The distance is 0.96m

Explanation:

Given

m1= 900kg

m2= 1600kg

Force F= 0.0001nN

G=6.67430*10^-11 Nm^2/kg^2

Required

The distance r

Step two:

the formula for the force is given as

F = Gm1m2/r2

make r subject of the formula

$r= \sqrt{\frac{Gm1m2}{F} }$

$r= \sqrt{\frac{6.67430*10^-11*900*1600}{0.0001} }\\\\r= 0.00009610992/0.0001`}\\\\r= 0.96m$

Answer:

The distance is 0.96m

Explanation:

Given

m1= 900kg

m2= 1600kg

Force F= 0.0001nN

G=6.67430*10^-11 Nm^2/kg^2

Required:

The distance r

Step two:

the formula for the force is given as

F = Gm1m2/r2

make r subject of the formula

$r= \sqrt{\frac{Gm1m2}{F} }$

$r= \sqrt{\frac{6.67430*10^-11*900*1600}{0.0001} }\\\\r= 0.00009610992/0.0001`}\\\\r= 0.96m$

3 0

3 years ago

Read 2 more answers

A long string is pulled so that the tension in it increases by a factor of four. If the change in length is negligible, by what

rusak2 [61]

To solve this problem we will apply the concepts related to wave velocity as a function of the tension and linear mass density. This is

$v = \sqrt{\frac{T}{\mu}}$

Here

v = Wave speed

T = Tension

$\mu$ = Linear mass density

From this proportion we can realize that the speed of the wave is directly proportional to the square of the tension

$v \propto \sqrt{T}$

Therefore, if there is an increase in tension of 4, the velocity will increase the square root of that proportion

$v \propto \sqrt{4} = 2$

The factor that the wave speed change is 2.

3 0

3 years ago

Does Anybody Know The Answers?

ch4aika [34]

Answer:

I was going to give you the paper where I saw it but since you are not giving enough points I can not give you so I am only going to give you some of these that are here sorry

Explanation:

$9^{2} + 12^2 = x^2\\81 + 144= x^2\\\sqrt{225} = \sqrt{x} \\ 15=x\\\\ 2.\\x^2+12^2+=13^2\\x^2+144 =169\\x^2 = 25\\\sqrt{x^2 =\sqrt{25\\\\$

x=5

$3.\\12^2+32^2 = x^2\\34.176= x$

5,12,13

$\frac{x}{4} ,\frac{12}{4} ,\frac{20}{4}\\\\\frac{x}{4},3,5 \\\\x=16\\\\12. \\x^2 + 48^2=50^2\\\\x^2=196\\x=14$

Download docx

5 0

3 years ago

When an object is in orbit, it is falling at the same rate at which the Earth is curving. Please select the best answer from the

olga2289 [7]

The statement “When an object is in orbit, it is falling at the same rate at which the Earth is curving” is true. The speed of a satellite orbiting the earth depends only on the mass of the earth and the mass of the satellite.

7 0

3 years ago