Which philosopher caused the “death” of the field of chemistry for 2000 years? *
1 answer:
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The total electrostatic force on charge A is
Explanation:
The magnitude of the electrostatic force between two charges is given by Coulomb's law:
where:
is the Coulomb's constant
are the two charges
r is the separation between the two charges
Here we have three positively charged particles A,B and C, located at the following positions:
The magnitudes of the three charges are:
The force exerted by B on A is to the left (because the force between two positive charges is repulsive), and the force exerted by C on A is also to the left (also repulsive). Therefore, the net force on A is just the sum of the two forces exerted by charges B and C:
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Answer:
a = 9.81[m/s^2]; v = 18683.5[m/s]
Explanation:
The stament of the problem is:
Suppose that the man pictured on the front side is orbiting the earth (mass = 5.98 x 1024kg) at a distance of 310 miles (1600 meters = 1 mile) above the surface of the earth (radius = 4000 miles).
a. What acceleration does he experience due to the earth's pull?
b. What tangential velocity must he possess in order that he orbit safely (in m/s)?
First we need to convert all the initial data to units of the SI
Rs = 310 [mil] = 498897 [m]
RT= 400 [mil] = 643738 [m]
r = Rs + RT = 1142635 [m] "distance from the center of the earth to the man"
G = universal gravitational constant
M = mass of the earth [kg]
m = mass of the man [kg]
r = distance from the center of the earth to the man [m]
a)
The acceleration he is experimenting is the same acceleration given by the gravity, therefore:
a = g = 9.81[m/s^2]
b)
To find the tangential velocity, we must determinate the force exerted by the earth.
Now we will find the force exerted by the gravity when the man is orbiting the earth at distance r.
And this force will be equal to the following expression: