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4 years ago

In a spacecraft, this reaction occurs:

Chemistry

1 answer:

viva [34]4 years ago

8 0

Volume of carbon dioxide absorbed = 33.6 L ≈ 34 L

Explanation:

We have the following chemical reaction:

CO₂ (g) + 2 LiOH (s) → Li₂CO₃ (s) + H₂O (l)

Now we devise the following reasoning:

if 1 mole of carbon dioxide reacts with 2 moles of lithium hydroxide

then X moles of carbon dioxide reacts with 3 moles of lithium hydroxide

X = (1 × 3) / 2 = 3/2 moles of carbon dioxide

And we calculate the volume of carbon dioxide using the following formula:

number of moles = volume / 22.4

volume = number of moles × 22.4

note: units for 22.4 are "L / mole"

volume of carbon dioxide = (3/2) × 22.4 = 33.6 L ≈ 34 L

Learn more about the reaction of carbon dioxide with metal hydroxides:

brainly.com/question/6979534

brainly.com/question/4316721

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According to the following electron structure, how many valence electrons does carbon have? C = 1s22s22p2

Sliva [168]

It is four valence electrons

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3 years ago

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Answer:

4486

Explanation:

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3 years ago

Given the two half-reactions, what must be done in the next step before the reaction can be balanced? Au3+ --> Au I- --> I

Artyom0805 [142]

Answer:

The balance equation is

$2Au^{+3} + 6I^{-}$ → $2Au + 3I_{2}$

Explanation:

first, we have to make sure that the atoms are balanced

$Au^{+3}$ → $Au^{}$

$2I^{-}$ → $I_{2}$

then we proceed to balance charges of each half-reaction

$Au^{+3} + 3e^{-}$ → $Au^{}$

$2I^{-}$ → $I_{2}$ $+ 2e^{-}$

Now we multiply the half-reactions to match the number of electrons in each one

( $Au^{+3} + 3e^{-}$ → $Au^{}$ )x2

( $2I^{-}$ → $I_{2}$ $+ 2e^{-}$ )x3

and now we do the sum of the half-reactions

2 $Au^{+3} + 6e^{-}$ → 2 $Au^{}$

$6I^{-}$ → 3 $I_{2}$ $+ 6e^{-}$

$2Au^{+3} + 6I^{-}$ → $2Au + 3I_{2}$

note: the only atom that needed to be balanced was I

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4 years ago

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Need answer quick please

Nikolay [14]

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using avogadro’s law

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3 years ago

What is the temperature change if 400 J of energy is added to 10 grams of water

Gemiola [76]

The temperature change if 400 J of energy is added to 10 grams of water is 9.57°C.

<h3>How to calculate temperature change?</h3>

The temperature change of a calorimeter can be calculated using the following expression:

E = mc∆T

Where;

E = energy in joules
m = mass
c = specific heat capacity = 4.18J/g°C
∆T = change in temperature

400 = 10 × 4.18 × ∆T

400 = 41.8∆T

∆T = 400/41.8

∆T = 9.57°C

Therefore, the temperature change if 400 J of energy is added to 10 grams of water is 9.57°C.

Learn more about change in temperature at: brainly.com/question/11464844

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