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Virty [35]
2 years ago
8

How do the frequency and amplitude affect the sound?

Physics
2 answers:
fenix001 [56]2 years ago
7 0
The sound is perceived as louder if the amplitude increases, and softer if the amplitude decreases. ( for amplitude)

Since sound at all frequencies has the same speed in air, a change in frequency means a change in wavelength. ( for frequency)
nalin [4]2 years ago
6 0
A higher frequency corresponds to a higher pitch while a lower frequency corresponds to a lower pitch. Amplitude corresponds to the loudness of sound.
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The suspension system of a 1700 kg automobile "sags" 7.7 cm when the chassis is placed on it. Also, the oscillation amplitude de
spin [16.1K]

Answer:

the spring constant k = 5.409*10^4 \ N/m

the value for the damping constant \\ \\b = 1.518 *10^3 \ kg/s

Explanation:

From Hooke's Law

F = kx\\\\k =\frac{F}{x}\\\\where \ F = mg\\\\k = \frac{mg}{x}\\\\given \ that:\\\\mass \ of \ each \ wheel = 425 \ kg\\\\x = 7.7cm = 0.077 m\\\\g = 9.8 \ m/s^2\\\\Then;\\\\k = \frac{425 \ kg * 9.8 \ m/s^2}{0.077 \ m}\\\\k = 5.409*10^4 \ N/m

Thus; the spring constant k = 5.409*10^4 \ N/m

The amplitude is decreasing 37% during one period of the motion

e^{\frac{-bT}{2m}}= \frac{37}{100}\\\\e^{\frac{-bT}{2m}}= 0.37\\\\\frac{-bT}{2m} = In(0.37)\\\\\frac{-bT}{2m} = -0.9943\\\\b = \frac{2m(0.9943)}{T}\\\\b = \frac{2m(0.9943)}{\frac{2 \pi}{\omega}}\\\\b = \frac{m(0.9943) \ ( \omega) )}{ \pi}

b = \frac{m(0.9943)(\sqrt{\frac{k}{m})}}{\pi}\\\\b = \frac{425*(0.9943)(\sqrt{\frac{5.409*10^4}{425}) }    }{3.14}\\\\b = 1518.24 \ kg/s\\\\b = 1.518 *10^3 \ kg/s

Therefore; the value for the damping constant \\ \\b = 1.518 *10^3 \ kg/s

5 0
3 years ago
A 50.0-turn circular coil of radius 5.00 cm can be oriented in any direction in a uniform magnetic field having a magnitude of 0
Blababa [14]

Answer:

The maximum torque in the coil is 4.9\times 10^{-3}\ N-m.

Explanation:

Given that,

Number of turns in the circular coil, N = 50

Radius of coil, r = 5 cm

Magnetic field, B = 0.5 T

Current in coil, I = 25 mA

We need to find the magnitude of the maximum possible torque exerted on the coil. The magnetic torque is given by :

\tau=NIAB\ \sin\theta

For maximum torque, \theta=90^{\circ}

\tau=NIAB\\\\\tau=50\times 25\times 10^{-3}\times \pi (0.05)^2\times 0.5\\\\\tau=4.9\times 10^{-3}\ N-m

So, the maximum torque in the coil is 4.9\times 10^{-3}\ N-m.

4 0
3 years ago
Electricity does not commonly occur in nature except in the form of ( hydrocarbons, photosyntheis, lightning, thunder)
horrorfan [7]
Hydrocarbons are compounds of hydrogen and carbon.
Photosynthesis is a process of nutrition in plants.
Thunder is a sound.
Lightning and electric eels are electrical phenomena in nature.
7 0
3 years ago
Read 2 more answers
In the modern model of the atoms over 99.9% of the atoms is made up of:
QveST [7]
In the modern model of the atoms over 99.9℅ of the atom is made up of empty space
3 0
3 years ago
Read 2 more answers
A sphere of metal has a mass of 1431 g and a diameter of 5.80 cm. What is the density of metal in g/cm3
Dmitriy789 [7]

Answer:

see below

Explanation:

You will need t find the volume of the sphere

 4/3 pi r^3    divide into the mass

1431 / (4/3 pi (5.8)^3) = 14 gm /cm^3

4 0
2 years ago
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