Answer:
net force= 2000-1000=1000
a=v-u/t=5/20=1/4
m=?
m=f/a
=1000÷1/4=4000kg
Answer:
a roller coaster at top.on hill
The 2 sides of magnet are called the north and south pole
Responder:
T = 0.25 segundos
f = 4 Hz
Explicación:
Paso uno:
datos dados
se nos dice que las partículas tardan 0,25 segundos en completar una vibración
por lo tanto, el período es de 0,25 segundos
¿Qué es un período de vibración?
Un período T es el tiempo necesario para que un ciclo completo de vibración pase por un punto determinado.
la expresión para el período se da a continuación.
T = 1 / f
¿Cuál es la frecuencia de vibración?
Básicamente, se refiere a la frecuencia con la que ocurren las vibraciones.
la frecuencia es una tasa, se expresa como la inversa del período
f = 1 / T
t = 1 / 0.25
f = 4 Hz
Answer:
The new pressure of the gas is 15.40 kPa.
Explanation:
Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. Mathematically this law indicates that the quotient between pressure and temperature is constant:

On the other hand, Boyle's law says that the volume occupied by a certain gaseous mass at constant temperature is inversely proportional to the pressure. This law is expressed mathematically as:
P*V=k
Finally, Charles's law indicates that as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. Mathematically, this law says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

Studying an initial state 1 and a final state 2, it is fulfilled:

In this case:
- P1= 10 kPa
- V1= 200 L
- T1= 0 C= 273 K
- P2=?
- V2= 175 L
- T2= 95 C= 368 K
Replacing:

Solving:

P2= 15.40 kPa
<u><em>The new pressure of the gas is 15.40 kPa.</em></u>