Answer:
Explanation:
given,
coefficient of kinetic friction, μ = 0.25
Speed of sled at point A = 8.6 m/s
Speed of sled at point B = 5.4 m/s
time taken to travel from point A to B.
we know,
J = F Δ t
J is the impulse
where F is the frictional force.
t is the time.
we also know that impulse is equal to change in momentum.
frictional force
F = μ N
where as N is the normal force
now,
time taken to move from A to B is equal to 1.31 s
Answer:
The coefficient of friction is 0.38.
Explanation:
The free body diagram is drawn below.
Let be frictional force acting in the backward direction as shown. Let the coefficient of friction be
. Let
be the normal reaction force acting on the bag.
Given:
Mass of the bag is,
Force acting at ° is
Acceleration due to gravity is,
The force F can be resolved into its components as and
Therefore,
Now, as there is no acceleration in vertical direction, therefore,
Sum of upward forces = Sum of downward forces
Now, as the bag is moving at a constant speed, so acceleration in the horizontal direction is also zero as acceleration is the rate of change of velocity.
Therefore, backward force = forward force.
Now, frictional force is given as:
Therefore, the coefficient of friction is 0.38.
To solve the problem it is necessary to consider the concepts related to Potential Energy and Kinetic Energy.
Potential Energy because of a planet would be given by the equation,
Where,
G = Gravitational Universal Constant
M = Mass of Ocean
M = Mass of Moon
r = Radius
From the data given we can calculate the mass of the ocean water through the relationship of density and volume, then,
It is necessary to define the two radii, when the ocean is far from the moon and when it is facing.
When it is far away, it will be the total diameter from the center of the earth to the center of the moon.
When it's near, it will be the distance from the center of the earth to the center of the moon minus the radius,
PART A) Potential energy when the ocean is at its furthest point to the moon,
PART B) Potential energy when the ocean is at its closest point to the moon
PART C) The maximum speed. This can be calculated through the conservation of energy, where,