Given :
A box weighing 12,000 N is parked on a 36° slope.
To Find :
What will be the component of the weight parallel to the plane that balances friction.
Solution :
The component of that will be parallel to the plane to balance friction is :
Therefore, component of force to balance friction is F sin 36° .
Hence, this is the required solution.
Answer:
Explanation:
14 lb force is required to stretch the spring by 4 inch distance
So we have
stretch in the spring is given as
now we will have
Now we need to find the work to stretch it by x = 10 in = 0.254 m
so we have
Answer:
Average speed = 0.0075 m/s
Average velocity = 0.0025 m/s along forward direction
Explanation:
Speed is the ratio of distance and time and velocity is the ratio of displacement and time.
Distance traveled = 10 + 5 = 15 cm = 0.15 m
Displacement = 10 - 5 = 5 cm = 0.05 m
Time = 20 seconds
Average speed = 0.0075 m/s
Average velocity = 0.0025 m/s along forward direction