Answer:
SN2
Explanation:
The first step of ether cleavage is the protonation of the ether since ROH is a better leaving group than RO-.
The second step of the reaction may proceed by either SN1 or SN2 mechanism depending on the structure of the ether. Methyl and primary ethers react with HI by SN2 mechanism while tertiary ethers react with HI by SN1 mechanism. Secondary ethers react with HI by a mixture of both mechanisms.
Dipentyl ether is a primary ether hence when treated with HI, the reaction with HI proceeds by SN2 mechanism as explained above.
To reduce a haloalkane, it has to be eliminated first. This is because 2 bromopropanes are a saturated compound that can not be reduced by a saturated compound. Dehydrohalogenation of the haloalkanes into the form of propene and hydrogen bromide can lead to the elimination. The propene is then reduced to propane.
Answer:
Pentasulfur nonanitride.
Explanation:
In order to name a compound properly, we need to identify the type of a compound we have. The given compound consists of two non-metals, sulfur and nitrogen. This implies that we have a covalent compound in contrast to an ionic compound which consists of a metal and a non-metal.
To name a molecular/covalent compound, we should use prefixes stating the number of atoms we have. In this case, we have 5 sulfur atoms. The prefix for 5 is 'penta'. That said, we have 'pentasulfur' as our beginning of the name.
We also have 9 nitrogen atoms. The second atom in the molecular formula would have an ending of '-ide', so we expect to have 'nitride'. Adding a prefix for 9, we'd have 'nonanitride'.
Putting everything together, the name is pentasulfur nonanitride.
Some common prefixes:
mono – one (we don't state mono for the first atom, e. g., we would name CO as carbon monoxide instead of monocarbon monoxide);
di – two;
tri – three;
tetra – four;
penta – five;
hexa – six;
hepta – seven;
octa – eight;
nona – nine;
deca – ten.
Notice that 'decanitride' would be correct in case you had 10 nitrogen atoms, similarly, tetra and hexa stand for 4 and 6 instead of 5 given sulfur atoms.
The heat of the reaction is an extensive property: it is proportional to the quantity of the quantity that reacts.
The change in enthalpy is a measured of the heat evolved of absorbed.
When the heat is released, the change in enthalpy is negative.
The reaction of 2 moles of Na develops 368.4 kj of energy.
Calculate the number of moles of Na in 1.90 g to find the heat released when this quantity reacts.
Atomic mass of Na: 23 g/mol
#mol Na = 1.90 g / 23 g/mol = 0.0826 mol
Do the ratios: [368.4 kj/2mol ] * 0.0826 mol = 15.21 kj.
Then the answer is that 15.21 kj of heat is released (evolved)
Answer:
As any molecular or ionic compound, 0 net charge, as a hypothetical diatomic cation, 2+
Explanation:
The question states that this is a compound, and any molecular or ionic compound would have a net charge of 0.
However, such a compound doesn't exist. Francium generally exists in nature having a 1+ charge in its cation form. Combining two francium ions would result in a 
species which is simply a diatomic ion but not a compound.
