Answer:
i dont know what you're asking here. But if you're asking what it is then:
Explanation:
Aluminum Hydroxide + Hydrogen Chloride = Aluminum Chloride + Water
Al and Oh3: Aluminum Hydroxide
H and Cl: Hydrogen Chloride
Al and Cl3: Aluminum Chloride
H2O: water
btw the first letter of every element should be capitalized. While the second and theird are lowercased.
Answer:
Yes. Ca²⁺(aq) + SO₄²⁻(aq) ⟶ CaSO₄(s)
Step-by-step explanation:
The possible reaction is
CaI₂ + Na₂SO₄ ⟶ CaSO₄ + 2NaI
To predict a reaction, you must know <em>the solubility rules</em>.
The important ones for this question are
- Salts containing Na⁺ are <em>soluble</em>. Thus, NaI is soluble.
- Most sulfates are soluble, but CaSO₄ is not. Thus, CaSO₄ is a precipitate, and a reaction occurs.
Molecular equation
CaI₂(aq) + Na₂SO₄(aq) ⟶ CaSO₄(s) + 2NaI(aq)
Ionic equation
Ca²⁺(aq) + <u>2I⁻(aq)</u> + 2Na²⁺(aq) + SO₄²⁻(aq) ⟶ CaSO₄(s) + 2Na⁺(aq) + 2I⁻(aq)
Net ionic equation
Cancel all ions that appear on both sides of the reaction arrow (underlined).
Ca²⁺(aq) + <u>2I⁻(aq) </u>+ <u>2Na²⁺(aq)</u> + SO₄²⁻(aq) ⟶ CaSO₄(s) + <u>2Na⁺(aq)</u> + <u>2I⁻(aq)
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The net ionic equation is
Ca²⁺(aq) + SO₄²⁻(aq) ⟶ CaSO₄(s)
Answer:
Explanation:
In calorimetry we apply the formula
heat lost = heat gained
m₁ x s₁ t ₁ = m₂ x s₂ t ₂
here t₁ and t₂ are change in temperature . suppose s₁ denotes specific heat of metal a nd s₂ denotes specific heat of water .
If s₁ is far less than s₂ , t₁ will be far more than t₂ , to balance the two sides
Hence change in temperature of metal pot will be more than change in temperature of water.
Final temperature will be far away from temperature of the metal pot.
Final temperature will be closer to temperature of water.
The element that has the fewest valence electrons available for bonding I believe is Hydrogen.