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4 years ago

PLEASE HELP! DUE IN 5 MINUTES! ( 10 points )

Chemistry

2 answers:

Tom [10]4 years ago

4 0

Answer:

This is what i got from google, so i would say C.)

Explanation:

Name Gold

Atomic Mass 196.967 atomic mass units

Number of Protons 79

Number of Neutrons 118

Number of Electrons 79

max2010maxim [7]4 years ago

3 0

Answer:

Explanation:

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You have 125.0 mL of a solution of H3PO4, bu you don't know its concentration. if you titrate the solution with a 4.56-M solutio

irakobra [83]

Answer:

4.90 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = ? M

V₁ = 125.0 mL

M₂ = 4.56 M

V₂ = 134.1 mL

Using the above formula , the molarity of acid , can be calculated as ,

M₁V₁ = M₂V₂

Substituting the respective values ,

M₁ * 125.0 mL = 4.56 M * 134.1 mL

M₁ = 4.90 M

6 0

4 years ago

Which of the following statements about benzene is true? Multiple Choice

fenix001 [56]

Answer: option a and d

Explanation:

Option A- Benzene undergoes substitution reaction

Example : benzene reacts with chlorine to form chlorobenzene, in the presence of Iron

(iii) chloride as a catalyst

C6H6 + Cl2 ---> C6H5Cl + HCl

Option D- Benzene also undergoes addition reaction

Example: benzene reacts with hydrogen , in the presence of nickel as a catalyst to form

cyclohexane

C6H6 + 3H2 ---> C6H12

Reasons why Option B isn't the answer

Although benzeme has degree of unsaturation but it's not five degree of unsaturation.

Benzene has 6 carbon atoms and 4 degrees of unsaturation (1 ring and 3 double

bonds).

If you work backwards and double the degrees of unsaturation you have 8 degrees of

unsaturation instead of 5.

Option C - Benzene isn't a saturated hydrocarbon

6 0

3 years ago

Which commercial technology commonly uses plasmas?

Ugo [173]

A television uses plasmas

8 0

3 years ago

Read 2 more answers

One reaction involved in the conversion of iron ore to the metal is FeO(s) + CO(g) → Fe(s) + CO2(g) Use Hess’s Law to calculate

Ugo [173]

Answer:

$\delta H_{rxn} = -66.0 \ kJ/mole$

Explanation:

Given that:

$3FeO_3_{(s)}+CO_{(g)} \to 2Fe_3O_4_{(s)} +CO_{2(g)} \ \ \delta H = -47.0 \ kJ/mole -- equation (1) \\ \\ \\ Fe_2O_3_{(s)} +3CO_{(g)} \to 2FE_{(s)} + 3CO_{2(g)} \ \ \delta H = -25.0 \ kJ/mole -- equation (2) \\ \\ \\ Fe_3O_4_{(s)} + CO_{(g)} \to 3FeO_{(s)} + CO_{2(g)} \ \delta H = 19.0 \ kJ/mole -- equation (3)$

From equation (3) , multiplying (-1) with equation (3) and interchanging reactant with the product side; we have:

$3FeO_{(s)} + CO_{2(g)} \to Fe_3O_4_{(s)} + CO_{(g)} \ \delta H = -19.0 \ kJ/mole -- equation (4)$

Multiplying (2) with equation (4) ; we have:

$6FeO_{(s)} + 2CO_{2(g)} \to 2Fe_3O_4_{(s)} + 2CO_{(g)} \ \delta H = -38.0 \ kJ/mole -- equation (5)$

From equation (1) ; multiplying (-1) with equation (1); we have:

$2Fe_3O_4_{(s)} +CO_{2(g)} \to 3FeO_3_{(s)}+CO_{(g)} \ \ \delta H = 47.0 \ kJ/mole -- equation (6)$

From equation (2); multiplying (3) with equation (2); we have:

$3 Fe_2O_3_{(s)} +9CO_{(g)} \to 6FE_{(s)} + 9CO_{2(g)} \ \ \delta H = -75.0 \ kJ/mole -- equation (7)$

Now; Adding up equation (5), (6) & (7) ; we get:

$6FeO_{(s)} + 2CO_{2(g)} \to 2Fe_3O_4_{(s)} + 2CO_{(g)} \ \delta H = -38.0 \ kJ/mole -- equation (5)$

$2Fe_3O_4_{(s)} +CO_{2(g)} \to 3FeO_3_{(s)}+CO_{(g)} \ \ \delta H = 47.0 \ kJ/mole -- equation (6)$

$3 Fe_2O_3_{(s)} +9CO_{(g)} \to 6FE_{(s)} + 9CO_{2(g)} \ \ \delta H = -75.0 \ kJ/mole -- equation (7)$

$FeO \ \ \ + \ \ \ CO \ \ \to \ \ \ \ Fe_{(s)} + \ \ CO_{2(g)} \ \ \ \delta H = - 66.0 \ kJ/mole$

$\delta H_{rxn} = \delta H_1 + \delta H_2 + \delta H_3$ (According to Hess Law)

$\delta H_{rxn} = (-38.0 + 47.0 + (-75.0)) \ kJ/mole$

$\delta H_{rxn} = -66.0 \ kJ/mole$

8 0

3 years ago

I need help please

Alex17521 [72]

Answer: If you think about it, B. would be the most reasonable answer with the given factors.

4 0

3 years ago