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Verizon [17]
3 years ago
5

PLEASE HELP! DUE IN 5 MINUTES! ( 10 points )

Chemistry
2 answers:
Tom [10]3 years ago
4 0

Answer:

This is what i got from google, so i would say C.)

Explanation:

Name Gold

Atomic Mass 196.967 atomic mass units

Number of Protons 79

Number of Neutrons 118

Number of Electrons 79

max2010maxim [7]3 years ago
3 0

Answer:

C

Explanation:

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In a reaction involving the iodination of acetone, the following volumes were used to make up the reaction mixture: 5 mL 4.0M ac
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Answer:

Explanation:

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7 0
3 years ago
Need help with this.
Jobisdone [24]

Answer:

18.2 g.

Explanation:

You need to first figure out how many moles of nitrogen gas and hydrogen (gas) you have. To do this, use the molar masses of nitrogen gas and hydrogen (gas) on the periodic table. You get the following:

0.535 g. N2 and 1.984 g. H2

Then find out which reactant is the limiting one. In this case, it's N2. The amount of ammonia, then, that would be produced is 2 times the amount of moles of N2. This gives you 1.07 mol, approximately. Then multiply this by the molar mass of ammonia to find your answer of 18.2 g.

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3 years ago
2. Which substance will form a solution with water? (Select all that app
cupoosta [38]

Answer:

sugar and salt, as they can dissolve in water. Sugar and salt have a high solubility in water. So, sugar and salt can form a solution with water.

Explanation:

7 0
2 years ago
Alcohols are polar molecules. true false
viktelen [127]
All alcohols are polar. True
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3 years ago
A buffer solution is composed of 1.00 mol of acid and 2.25 mol of the conjugate base. If the p K a of the acid is 4.90 , what is
Gemiola [76]

<u>Answer:</u> The pH of the buffer is 5.25

<u>Explanation:</u>

Let the volume of buffer solution be V

We know that:

\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution}}

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[\text{conjugate base}]}{[acid]})

We are given:

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[\text{conjugate base}]=\frac{2.25}{V}

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pH = ?

Putting values in above equation, we get:

pH=4.90+\log(\frac{2.25/V}{1.00/V})\\\\pH=5.25

Hence, the pH of the buffer is 5.25

4 0
3 years ago
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