All categories

2 years ago

I really need help on this question please help

Chemistry

1 answer:

nikitadnepr [17]2 years ago

8 0

I don’t know the answer either

You might be interested in

What is thr valency of scadium

Hoochie [10]

scandium is a transition metal and shows a valency of 3.

4 0

3 years ago

Using the periodic table, find the molecular mass of H2. H2 = g/mole

alekssr [168]

MH₂ = 2×mH = 2×1g = 2 g/mol

5 0

2 years ago

A mixture of 14.2 g of H2 and 36.7 g of Ar is placed in a 100.0 L container at

TiliK225 [7]

a) The total pressure of the system is 1.79 atm

b) The mole fraction and partial pressure of hydrogen is 0.89 and 1.59 atm respectively

c) The mole fraction and the partial pressure of argon is 0.11 and 0.19 atm.

<h3>What is the total pressure?</h3>

We know tat we can be able to obtain the total pressure in the system by the use of the ideal gas equation. We would have from the equation;

PV = nRT

P = pressure

V = volume

n = Number of moles

R = gas constant

T = temperature

Number of moles of hydrogen = 14.2 g/2g = 7.1 moles

Number of moles of Argon = 36.7 g/40 g/mol

= 0.92 moles

Total number of moles = 7.1 moles + 0.92 moles = 8.02 moles

Then;

P = nRT/V

P = 8.02 * 0.082 * 273/100

P = 1.79 atm

Mole fraction of hydrogen = 7.1/8.02 = 0.89

Partial pressure of hydrogen = 0.89 * 1.79 atm

= 1.59 atm

Mole fraction of argon = 0.92 / 8.02

= 0.11

Partial pressure of argon = 0.11 * 1.79 atm

= 0.19 atm

Learn more about partial pressure:brainly.com/question/13199169

#SPJ1

3 0

1 year ago

How do scientists use radioactive decay to date fossils

grin007 [14]

The clearer answer is they measure the remaining carbon, and the less that there is the older the fossil is.

7 0

3 years ago

In a titration experiment a student uses 1.4 m hbr solution and the indicator phenolphthalein to determine the concentration of

Likurg_2 [28]

The question is incomplete. Complete question is attached below:
...........................................................................................................................

Answer:
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL

We know that, M1V1 = M2V2
(HBr) (KOH)

Therefore, M2 = M1V1/V2
= 1.4 X 15.4/22.10
= 0.9756 M

Concentration of KOH is 0.9756 M.

3 0

3 years ago

Read 2 more answers