If x represents the width of the poster (including borders), the area of the finished poster can be written as
.. a = x*(390/(x -10) +8)
.. = 8x +390 +3900/(x -10)
Then the derivative with respect to x is
.. da/dx = 8 -3900/(x -10)^2
This is zero at the minimum area, where
.. x = √(3900/8) +10 ≈ 32.08 . . . . cm
The height is then
.. 390/(x -10) +8 = 8 +2√78 ≈ 25.66 . . . . cm
The poster with the smallest area is 32.08 cm wide by 25.66 cm tall.
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In these "border" problems, the smallest area will have the same overall dimension ratio that the borders have. Here, the poster is 10/8 = 1.25 times as wide as it is high.
Answer:
wait so what is the numbers of distance they have swam?
Step-by-step explanation:
Answer:
you have to sell 6 tables to meet all requirements
Step-by-step explanation:
chairs=$50x
tables=$550x
24 chairs×50= $1200
4100-1200= $2900
take $2900 and divide by $550 to find the exact number of tables which is 5 but selling 5 tables and 24 chairs doesnt reach the $4100 mark so I rounded up to 6 tables which doesnt surpass the maximum number of furniture(32) but beats the $4100 mark
Answer:
yes
Step-by-step explanation:
slope is 1 and points are (0,7)
