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3 years ago

Write the realtionship between the density of a liquid and its upthrust? clarify

Physics

1 answer:

kipiarov [429]3 years ago

8 0

Answer:

B = ρ g V_liquid

the thrust is proportional to the density of the liquid

Explanation:

The density of a liquid is defined as the relationship between the mass and the volume of the liquid

ρ = m / V

The upward push of the liquid is given by the principle of Archimedes Archimedes establishes that the push is equal to the weight of the dislodged liquid

B = W_liquid

B = m _liquid g

we substitute mass for density

B = ρ g V_liquid

therefore we see that the thrust is proportional to the density of the liquid

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A car is traveling at 21m/s. It accelerates at 1.4m/s2 for 11s. How fast is the car moving after the acceleration?

nata0808 [166]

Answer:

v=u+at

v=21+1.4(11)

v=21+15.4

v=36.4

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3 years ago

Two large parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm. Part A If the surfac

alukav5142 [94]

Answer:

5308.34 N/C

Explanation:

Given:

Surface density of each plate (σ) = 47.0 nC/m² = $47\times 10^{-9}\ C/m^2$

Separation between the plates (d) = 2.20 cm

We know, from Gauss law for a thin sheet of plate that, the electric field at a point near the sheet of surface density 'σ' is given as:

$E=\dfrac{\sigma}{2\epsilon_0}$

Now, as the plates are oppositely charged, so the electric field in the region between the plates will be in same direction and thus their magnitudes gets added up. Therefore,

$E_{between}=E+E=2E=\frac{2\sigma}{2\epsilon_0}=\frac{\sigma}{\epsilon_0}$

Now, plug in $47\times 10^{-9}\ C/m^2$ for 'σ' and $8.85\times 10^{-12}\ F/m$ for $\epsilon_0$ and solve for the electric field. This gives,

$E_{between}=\frac{47\times 10^{-9}\ C/m^2}{8.854\times 10^{-12}\ F/m}\\\\E_{between}= 5308.34\ N/C$

Therefore, the electric field between the plates has a magnitude of 5308.34 N/C

5 0

3 years ago

A crane lifts a load of 15000N to a height 40m in 50 seconds. Calculate the power of the crane

Nataly [62]

Answer:

P = 12000 W

Explanation:

General data:

F = 15000 N
d = 40 m
t = 50 s
P = ?

Work is force times unit of distance. So in order to calculate the power we must first calculate the work.

Formula:

$\boxed{\bold{W=\frac{F}{d}}}$

Replace and solve

$\boxed{\bold{W=\frac{15000\ N}{40\ m}}}$

$\boxed{\bold{W=600000\ J}}$

once the work is found, we proceed to find the power according to the formula:

$\boxed{\bold{P=\frac{W}{t}}}$

$\boxed{\bold{P=\frac{600000\ J}{50\ s}}}$

$\boxed{\boxed{\bold{P=12000\ W}}}$

The power of the crane is <u>12000 Watts.</u>

Greetings.

6 0

3 years ago

A mass of 10kg is a point a on a table is moved to a point B.if the line joining A and is horizantal what is the done on the obj

IrinaK [193]

Answer:

work done on the object by gravitational force = 0 joules

Explanation:

work = force × displacement

force = mass × acceleration

so,

work = mass × acceleration × displacement

we know that mass= 10 kg , gravitational acceleration= 9.8 $m/s^2$

and displacement= 0 m since the object is not moving vertically.

so,

work = 10 × 9.8 × 0 = 0 joules

6 0

2 years ago

Read 2 more answers

A hot-air balloon consists of a basket hanging beneath a large envelope filled with hot air. A typical hot-air balloon has a tot

Deffense [45]

Answer:

1.05045 kg/m³

Explanation:

$\rho_a$ = Density of air = 1.26 kg/m³

$\rho_{ha}$ = Density of hot air

$m_a$ = Mass of balloon = 539 kg

g = Acceleration due to gravity = 9.81 m/s²

v = Volume of air in balloon = $2.62\times 10^3\ m^3$

The net force on the balloon will be

$F_n=(\rho_a-\rho_{ha})vg$

Also

$F_n=m_ag$

$\\\Rightarrow 549g=(\rho_a-\rho_{ha})vg\\\Rightarrow 549=(1.26-\rho_{ha})2.62\times 10^3\\\Rightarrow -\rho_{ha}=\frac{549}{2.62\times 10^3}-1.26\\\Rightarrow \rho_{ha}=1.05045\ kg/m^3$

The density of hot air inside the envelope is 1.05045 kg/m³

4 0

3 years ago

Write the realtionship between the density of a liquid and its upthrust? clarify​

Write the realtionship between the density of a liquid and its upthrust? clarify