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n200080 [17]
2 years ago
12

Write the realtionship between the density of a liquid and its upthrust? clarify​

Physics
1 answer:
kipiarov [429]2 years ago
8 0

Answer:

B = ρ g V_liquid

the thrust is proportional to the density of the liquid

Explanation:

The density of a liquid is defined as the relationship between the mass and the volume of the liquid

         ρ = m / V

The upward push of the liquid is given by the principle of Archimedes Archimedes establishes that the push is equal to the weight of the dislodged liquid

        B = W_liquid

        B = m _liquid g

we substitute mass for density

        B = ρ g V_liquid

therefore we see that the thrust is proportional to the density of the liquid

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A light-year is the distance that light travels in one year. The speed of light is 3.00 × 108 m/s. How many miles are there in o
Alinara [238K]

Answer:

(a) 5.88\times 10^{12}mi

Explanation:

We have given speed of light c=3\times 10^8m/sec

Given time = 1 year =365 days

We know that in 1 minute = 60 sec

1 hour = 60×60 = 3600 sec

In one day = 24 hour = 24×60×60=86400 sec

So in 365 days = 365×86400=3.1536\times 10^7sec

We know that distance = speed ×time=3.1536\times 10^7\times 3\times 10^8=9.46\times 10^{15}m

We have given that 1 mi = 1609 m

So 9.46\times 10^{15}m=\frac{9.46\times 10^{15}}{1609}=5.88\times 10^{12}miSo option (a) is correct

8 0
3 years ago
Why does the frequency of a wave increase as the wavelength decreases
olchik [2.2K]

Explanation:

We know that the number of complete waves formed in 1 sec time is frequency and the distance between two consecutive crests or troughs is wavelength. And we have the formula that

Velocity = wavelength * frequency

or, frequency = velocity / wavelength

Here we can see frequency is directly proportional to velocity and indirectly proportional to wavelength.

So as the wavelength increases frequency decreases and as the wavelength decreases frequency increases.

Hope you understood

3 0
3 years ago
Read 2 more answers
When it is at rotating at full speed, a disk drive in a certain old computer game system revolves once every 0.050 seconds. Star
Gemiola [76]

Answer:

α = 200*π rad/sec²

Explanation:

  • If the disk drive revolves once every 0.05 sec, this means that the angular velocity can be expressed as follows:

        \omega = \frac{2*\pi}{0.05s} = 40*\pi rad/sec

  • (just applying the definition of angular velocity)
  • Now, it the disk started from rest, and took two revolutions to reach to full speed, assuming that the angular acceleration is constant, we can find the angular acceleration applying this kinematic equation:

        \omega_{f} ^{2} -\omega_{0} ^{2} = 2*\alpha * \Delta\theta

  • where Δθ, is the angle rotated while it went from rest to full speed, i.e., 2 revolutions, or 2*π rads.
  • Replacing by the value that we found for ωf (as ω₀ = 0), we  can solve for α :

       \alpha =\frac{\omega_{f}^{2} }{2*\Delta\theta} = \frac{(40*\pi)^{2} }{2*2*2*\pi } =\\ \\ \alpha = 200*\pi rad/sec2

3 0
3 years ago
If the acceleration of the projective is: a = c s m/s 2 Where c is a constant that depends on the initial gas pressure behind th
Sedbober [7]

Answer:

c = 4,444.44

Explanation:

You have the following expression for the acceleration of the projectile:

a=cs   (1)

s: distance to the ground of the projectile

To find the value of the constant c you use the following formula:

v^2=v_o^2+2a \Delta s   (2)

vo: initial  velocity = 0 m/s

v: final speed = 200 m/s

Δs: distance traveled by the projectile = 3m - 1.5m = 1.5m

You replace the expression (1) into the expression (2):

v^2=2(cs)\Delta s

You do the constant c in the last equation, then you replace the values of v, s and Δs:

c=\frac{v^2}{2s\Delta s}=\frac{(200m/s)^2}{2(3m/s^2)(1.5m)}=4444.44

6 0
3 years ago
Define projectile in your own .​
lorasvet [3.4K]

Answer:

a body which was thrown in space ,moves under the influence of gravity only is defined as projectile.

5 0
2 years ago
Read 2 more answers
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