Answer:
The ball will go to maximum height of 56.25 meters.
Step-by-step explanation:
It is given that, a ball is thrown vertically upward from the ground. Initial velocity of the ball, v = 60 ft/sec
Initial height is 0 as the ball is thrown from ground. The equation of projectile is given by :
h = 0
..............(1)
We need to find the maximum height reached by the ball. For maximum height,
t = 1.875 seconds
Put the values of t in equation (1). So,
h(t) = 56.25 meters
So, the ball will go to maximum height of 56.25 meters. Hence, this is teh required solution.
Answer:
Hi there!
Your answer is:
59.5%
Step-by-step explanation:
To chance a demical into a percent, multiply by 100!
.595 × 100 = 59.5%
I hope this helps!
The answer is -14 ........
Answer:
x=3+3/4
Step-by-step explanation:
1+4x/6=3.5
We move all terms to the left:
1+4x/6-(3.5)=0
We add all the numbers together, and all the variables
4x/6-2.5=0
We multiply all the terms by the denominator
4x-(2.5)*6=0
We add all the numbers together, and all the variables
4x-15=0
We move all terms containing x to the left, all other terms to the right
4x=15
x=15/4
x=3+3/4
Answer:
its 12
Step-by-step explanation:
you find whats closest for example, 10 squared is 100.
100 is close to 144
and 11x11= 121
so you would do 12
12x12 is 144
