Answer:
19,600
Step-by-step explanation:
0-49=50 numbers
n=50
r=3
C(n,r)=n!/(r!(n-r)!)
=50!/(47!)(3!)
C(n,r)=C(50,3)
=50!/(3!(50−3)!)
= 19600
Answer:
3137 + 3791
Step-by-step explanation:
you add all 3 first, lets try with the first one
3137 + 3791= 6928
Answer:
Price of advance ticket: 15$
Price of same-day ticket: $40
Step-by-step explanation:
Let
be the price of one advance ticket and
the cost of one same day ticket.
We know that the combined cost of one advance ticket and one same-day ticket is $55, so
equation (1)
We also know that 20 advance tickets and 35 same-day tickets cost $1700, so
equation (2)
Now, let's solve our system of equations step-by-step:
step 1. Solve for
in equation (1)

equation (3)
step 2. Replace equation (3) in equation (2)





equation (4)
step 3. Replace equation (4) in equation (3)



We can conclude that the price of one advance ticket is $15 and the price of one same-day ticket is $40.
Answer:
CP is 13 because 20-13=7 also you can subtract 20-7=13
So, here us your ans 13.