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vichka [17]
3 years ago
14

The Sun has more gravity than the other planets in our solar system because the Sun is

Physics
2 answers:
Likurg_2 [28]3 years ago
7 0

B would be your answer, did it on USAtestprep

IRISSAK [1]3 years ago
5 0
B the mass of the solar object determines whether the gravity of the object unless the solar object has Sonic property's such as a neutron star which can be the size of Pluto but have the mass of 900 solar masses
You might be interested in
An electron and a proton are both released from rest, midway between the plates of a charged parallel-plate capacitor. The only
topjm [15]

Answer:

Explanation:

Let the potential difference between the middle point and one of the plate be ΔV .

electric potential energy will be lost and it will be converted into kinetic energy .

Electrical potential energy lost = Vq , where q is charge on charge particle .

For proton

ΔV× q = 1/2 M V² ( kinetic energy of proton )

where M is mass and V be final velocity of proton .

For electron

ΔV× q = 1/2 m v² ( kinetic energy of electron  )

where m is mass and v be final velocity of electron . Charges on proton and electron are same in magnitude .

As LHS of both the equation are same , RHS will also be same . That means the kinetic energy of both proton and electron will be same

1/2 M V² =  1/2 m v²

(V / v )² = ( m / M )

(V / v ) = √ ( m / M )

In other words , their velocities  are  inversely proportional to square root of their masses .

4 0
3 years ago
1. An excited lithium atom emits a red light with wavelength a = 671nm. What is the corresponding photon energy? hc (6.63 x 10-3
Rudiy27

Answer:

 E = 2,964 10⁻¹⁹ J

Explanation:

The energy of the photons is given by the Planck relation

          E = h f

the speed of light is related to wavelength and frequency

          c = λ f

we substitute

          E = h c /λ

let's reduce the magnitude to the SI system

          λ = 671 nm = 671 10⁻⁹ m

let's calculate

          E = 6.63 10⁻³⁴ 3 10⁸ /671 10⁻⁹

          E = 2,964 10⁻¹⁹ J

6 0
3 years ago
In a certain process, the energy change of the system is 250 \rm kJ. The process involves 480 \rm kJ of work done by the system.
alisha [4.7K]

Answer:

\Delta Q=-230kJ

Explanation:

Using the first law of thermodynamics:

\Delta U=\Delta Q-W

Where \Delta U is the change in the internal energy of the system, in this case  \Delta U=250kJ, \Delta Q is the heat tranferred, and W is the work,  W=-480kJ with a negative sign since the work is done by the system.

From the previous equation we solve for heat, because it is the unknown variable in this problem

\Delta Q=\Delta U +W

And replacing the known values:

\Delta Q=250kJ +(-480kJ)

\Delta Q=250kJ -480kJ

\Delta Q=-230kJ

The negative sign shows us that the heat is tranferred from the system into the surroundings.

3 0
4 years ago
Two cars are raised to the same elevation on service- station lifts. If one car is twice as massive as the other, how do their p
Brums [2.3K]

Answer:

The potential energy of the more massive one is twice that of the other.

Explanation:

Potential energy is given by

<em>PE</em> = <em>mgh</em>

where <em>m</em> = mass of body, <em>g</em> = acceleration of gravity and <em>h</em> = height or elevation.

For the less massive car, let the mass be m_1. Then its <em>PE</em> is

PE_1 = m_1gh

For the massive car, let the mass be m_2.  Its <em>PE</em> is

PE_2 = m_2gh

But m_2 =2m_1

\therefore PE_2 = 2m_1gh = 2(m_1gh) = 2PE_1

Hence, the potential energy of the more massive one is twice that of the other.

7 0
4 years ago
A bowling ball of mass 5 kg rolls down a slick ramp 20 meters long at a 30 degree angle to the horizontal. What is the work done
Elena-2011 [213]

Answer:

The work done by gravity during the roll is 490.6 J

Explanation:

The work (W) is:

W = F*d

<em>Where</em>:

F: is the force

d: is the displacement = 20 m

The force is equal to the weight (W) in the x component:

F = W_{x} = mgsin(\theta)

<em>Where:</em>

m: is the mass of the bowling ball = 5 kg

g: is the gravity = 9.81 m/s²    

θ: is the degree angle to the horizontal = 30°        

F = mgsin(\theta) = 5 kg*9.81 m/s^{2}*sin(30) = 24.53 N    

Now, we can find the work:

W = F*d = 24.53 N*20 m = 490.6 J      

Therefore, the work done by gravity during the roll is 490.6 J.

I hope it helps you!

6 0
3 years ago
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