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3 years ago

Calculate the time it takes for an object moving with a speed of 13m/s to travel 50 m

Chemistry

1 answer:

kykrilka [37]3 years ago

7 0

Answer:

<h3>The answer is 3.85 s</h3>

Explanation:

The time taken can be found by using the formula

$t = \frac{d}{v} \\$

d is the distance covered

v is the velocity

From the question we have

$t = \frac{50}{13} \\ = 3.846153...$

We have the final answer as

Hope this helps you

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Calculate the atomic mass of silver if 13 out of 25 atoms are silver-107 and 12 out of 25 are silver-109

nekit [7.7K]

From,

RAM=element×its relative abudance/total abudance

=((107×13)+(12×109))/25

The answer is=107.96

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3 years ago

Chemistry Question! 20 Points!

Delvig [45]

Answer:

Explanation:

I guess it's a, because nuclear decay is likely to occur when either the mass or atomic number is greater than 83.

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3 years ago

Answer quickly i'm out of time !!!!!!

melamori03 [73]

Answer:

Option D. pH= 1.3 strong acid

Explanation:

From the question given:

The hydrogen ion concentration [H+] = 0.05 M

pH = —Log [H+]

pH = —Log 0.05

pH = 1.3

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3 years ago

The equilibrium constant for the reaction is 1.1 x 106 M. HONO(aq) + CN-(aq) ⇋ HCN(aq) + ONO-(aq) This value indicates that

kakasveta [241]

The given question is incomplete. The complete question is given here :

The equilibrium constant for the reaction is $1.1\times 10^6$ M.

$HONO(aq)+CN^- (aq)\rightleftharpoons HCN(aq)+ONO^-(aq)$

This value indicates that

A. $CN^-$ is a stronger base than $ONO^-$

B. HCN is a stronger acid than HONO

C. The conjugate base of HONO is $ONO^-$

D. The conjugate acid of CN- is HCN

Answer: A. $CN^-$ is a stronger base than $ONO^-$

Explanation:

Equilibrium constant is the ratio of product of the concentration of products to the product of concentration of reactants.

When $K_{p}>1$ ; the reaction is product favoured.

When $K_{p};$ ; the reaction is reactant favored.

$When K_{p}=1$ ; the reaction is in equilibrium.

As, $K_p>>1$ , the reaction will be product favoured and as it is a acid base reaction where $HONO$ acts as acid by donating $H^+$ ions and $CN^-$ acts as base by accepting $H^+$

Thus $HONO$ is a strong acid thus $ONO^-$ will be a weak conjugate base and $CN^-$ is a strong base which has weak $HCN$ conjugate acid.

Thus the high value of K indicates that $CN^-$ is a stronger base than $ONO^-$

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3 years ago

How do a strong electrolyte, weak electrolyte, and non-electrolyte differ in the number of ions each produces when dissolved in

Dmitrij [34]

Strong electrolytes are completely ionised in solution.
Weak ones are only partially ionised.
Non electrolytes do not form ions

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3 years ago