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velikii [3]
3 years ago
12

A pyrotechnical expert needs to fire a 15 kg projectile from a launching device that has a barrel length of 2 meters. The projec

tile will need to be launched horizontally 1 km in 5 seconds. Calculate the force needed to launch the projectile.
Physics
1 answer:
Furkat [3]3 years ago
7 0

Answer:

The force needed to launch the projectile is 150000 N.

Explanation:  

We can find the force using the following equation:

F = ma

Where:

m: is the mass = 15 kg

a: is the acceleration

First, we need to find the acceleration of the projectile:

v_{f}^{2} = v_{0}^{2} + 2ax                          

Where:

v_{f}: is the final speed

v_{0}: is the initial speed = 0

x: is the distance = 2 m

The final speed is:

v_{f} = \frac{1 km}{5 s}*\frac{1000 m}{1 km} = 200 m/s

Then, the acceleration is:

a = \frac{v_{f}^{2}}{2x} = \frac{(200 m/s)^{2}}{2*2 m} = 10000 m/s^{2}

Finally, the force is:

F = ma = 15 kg*10000 m/s^{2} = 150000 N

Therefore, the force needed to launch the projectile is 150000 N.

I hope it helps you!  

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Answer:

c. V = 2 m/s

Explanation:

Using the conservation of energy:

E_i =E_f

so:

Mgh = \frac{1}{2}IW^2 +\frac{1}{2}MV^2

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Also we know that:

V = WR

Where R is the radius of the disk, so:

W = V/R

Also, the moment of inertia of the disk is equal to:

I = \frac{1}{2}MR^2

I = \frac{1}{2}(5kg)(2m)^2

I = 10 kg*m^2

so, we can write the initial equation as:

Mgh = \frac{1}{2}IV^2/R^2 +\frac{1}{2}MV^2

Replacing the data:

(5kg)(9.8)(0.3m) = \frac{1}{2}(10)V^2/(2)^2 +\frac{1}{2}(5kg)V^2

solving for V:

(5kg)(9.8)(0.3m) = V^2(\frac{1}{2}(10)1/4 +\frac{1}{2}(5kg))

V = 2 m/s

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4 years ago
Organic macromolecules called _______ are insoluble in water
NikAS [45]

Answer:

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3 0
3 years ago
The dark bands on the wall are from ______________ interference. and i will give brainlyest
Fittoniya [83]
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4 0
4 years ago
Describe liquids and GASSES IN TERMS OF THERE VOLUME AND SHAPES
antiseptic1488 [7]

Answer:

Explanation:

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gases do not have definite volume.

gases do not have definite shape. They take the shape of the container in which they are kept.

Hope this helps

plz mark as barinliest!!!!!!

Stay safe!

3 0
3 years ago
Read 2 more answers
What must be the units for the gravitational constant G in order for gravitational force to have units of newtons?
babunello [35]

Answer:

m³/(kg⋅s²)

Explanation:

Hello.

In this case, since the involved formula is:

F=G*\frac{m_1m_2}{r^2}

By writing a dimensional analysis with the proper algebra handling, we obtain:

N[=]G*\frac{kg*kg}{m^2}\\ \\kg*\frac{m}{s^2}[=]G *\frac{kg*kg}{m^2}\\\\G[=]\frac{kg*m*m^2}{kg^2*s^2}\\ \\G[=]\frac{m^3}{kg*s^2}

Thus, answer is:

m³/(kg⋅s²)

Note that the [=] is used to indicate the units of G.

Best regards

4 0
3 years ago
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