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velikii [3]
3 years ago
12

A pyrotechnical expert needs to fire a 15 kg projectile from a launching device that has a barrel length of 2 meters. The projec

tile will need to be launched horizontally 1 km in 5 seconds. Calculate the force needed to launch the projectile.
Physics
1 answer:
Furkat [3]3 years ago
7 0

Answer:

The force needed to launch the projectile is 150000 N.

Explanation:  

We can find the force using the following equation:

F = ma

Where:

m: is the mass = 15 kg

a: is the acceleration

First, we need to find the acceleration of the projectile:

v_{f}^{2} = v_{0}^{2} + 2ax                          

Where:

v_{f}: is the final speed

v_{0}: is the initial speed = 0

x: is the distance = 2 m

The final speed is:

v_{f} = \frac{1 km}{5 s}*\frac{1000 m}{1 km} = 200 m/s

Then, the acceleration is:

a = \frac{v_{f}^{2}}{2x} = \frac{(200 m/s)^{2}}{2*2 m} = 10000 m/s^{2}

Finally, the force is:

F = ma = 15 kg*10000 m/s^{2} = 150000 N

Therefore, the force needed to launch the projectile is 150000 N.

I hope it helps you!  

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A box with mass 25.14 kg is sliding at rest from the top of the slope with height 13.30 m
lutik1710 [3]

Answer:

Explanation:

The first thing we are asked to find is the Force experienced by the box. That is found in the formula:

F - f = ma where F is the force exerted by the box, f is the friction opposing the box, m is the mass, and a is the acceleration (NOT the same as the pull of gravity). But F can be rewritten in terms of the angle of inclination also:

wsin\theta-f=ma where w is the weight of the box. We will use this version of the formula because it will help us answer the second question, which is to solve for a. Filling in:

First we need the weight of the box. Having the mass, we find the weight:

w = mg so

w = 25.14(10) so

w = 251.4 N (I am not paying any attention at all to the sig fig's here, since I noticed no one on this site does!) Now we have the weight. Filling that in:

251.4sin(30) - f = ma Before we go on to fill in for f, let's answer the first question. F = 251.4sin(30) so

F = 125.7   And in order to answer what a is equal to, we find f:

f = μF_n where Fn is the weight of the object.

f = .25(251.4) so

f = 62.85. Filling everything in now altogether to solve for a, the only missing value:

125.7 - 62.85 = 25.14a and

62.85 = 25.14a so

a = 2.5 m/s/s

Now we have to move on to another set of equations to answer the last part. The last part involves the y-dimension. In this dimension, what we know is that

a = -10 m/s/s

v₀ = 0 (it starts from rest)

Δx = -13.30 m (negative because the box falls this fr below the point fro which it started). Putting all that together in the equation for displacement:

Δx = v₀t + \frac{1}{2}at^2 and we are solving for time:

-13.30=0t+\frac{1}{2}(-10)t^2 and

t=\sqrt{\frac{2(-13.30)}{-10} } so

t = 1.6 seconds to reach the bottom of the slope from 13.30 m high.

3 0
3 years ago
Galileo discovered that which planet undergoes phases as viewed from earth?
balu736 [363]
<h2>Answer: Venus</h2>

Galileo was the first to use the telescope to observe the heavens, mainly observing the Moon, the Sun with its sunspots, Jupiter with its moons and Venus (in the early 1600s).

In the case of Venus, he observed that it presented phases (such as those of the moon) together with a variation in size; observations that are only compatible with the fact that Venus rotates around the Sun and not around Earth.

This is because Venus presented its smaller size when it is in full phase and the largest size when it is in the new one, when it is between the Sun and the Earth.

These images along with other discoveries were presented to the Catholic Church (which supported the <u>geocentric theory</u> for that time) as a proof that completely refutes Ptolemy's geocentric system and affirms <u>Copernicus' heliocentric theory.</u>

3 0
3 years ago
If a guitar string vibrates 20 times each second,what is its frequency?
vampirchik [111]
The answer is 20. Frequency is "number of times" per unit time.
4 0
4 years ago
Read 2 more answers
What is the minimum angular spread (in rad) of a 534 nm wavelength manganese vapor laser beam that is originally 1.19 mm in diam
Ad libitum [116K]

Answer:

Minimum angular spread (in rad) = 547.45 x 10⁻⁶ rad

Explanation:

GIven;

Wavelength of manganese vapor laser beam = 534 nm = 534 x 10⁻⁹ m

Diameter =  1.19 mm = 1.19 x 10⁻³ m

Find:

Minimum angular spread (in rad)

Computation:

Minimum angular spread (in rad) = 1.22[Wavelength / Diameter]

Minimum angular spread (in rad) = 1.222[(534 x 10⁻⁹) / (1.19 x 10⁻³)]

Minimum angular spread (in rad) = 2[448.73 x 10⁻⁶]

Minimum angular spread (in rad) = 547.45 x 10⁻⁶ rad

6 0
3 years ago
a 15.0k resistor is hooked up to 45.0v battery in a circuit with a switch a.) Draw a circuit diagram for the circuit described.
Luda [366]
For item#1 , see attached picture, there is a voltage source, a resistor and wire (where current flow).

For item#2, we use the formula V=IR where "V" is for the voltage, "I" is for the current and "R" for the resistance
Solving for I:
I = v/r
I = 45volts/15k ohms
I=3 mA

For item#3, power is P=VI 
p = 45volts * 3ma
P = 0.135 Watts

7 0
4 years ago
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