Answer:
The SAE curriculum includes practical farming tasks conducted outside the scheduled classroom and laboratory period by students. SAEs offer a method for students in agricultural education to gain real-world work opportunities that they are most interested in in the field of agriculture. Supervised agricultural experience is an essential component of agricultural education, and all Agriculture, Food and Natural Resources (AFNR) courses are a necessary component.
Explanation: Hope it helps
It is really very important to know where the safety equipments are placed in lab because when we know it then accident wont occur in lab . it will also helps us to feel secure while doing any kinds of experiment
Answer: Option D) covalent bonds between water molecules
In water, hydrogen bonds are best described as covalent bonds between water molecules
Explanation:
The hydrogen bonds between water molecules are covalent bonds because they are formed when oxygen attract the lone electron in hydrogen, thus resulting in the formation of a partially negative charge on the oxygen atom and a partially positive charge on two hydrogen atoms
Thus, the sharing of electrons between oxygen and hydrogen atoms is responsible for the covalent bonds between water molecules
Answer:
b
. Irradiated food is shown to not be radioactive.
Explanation:
If it can be proven that irradiated food is not radioactive, then it will effective dispute the idea that irradiated food are less safe to eat.
- An irradiated food is one in which ionizing radiations have been employed to improve food quality.
- Thus, bacteria and other food spoilers can be exterminated from the food.
- Most irradiated food do not contain radiation and are fit for consumption.
If it can be proven, that this is true, then it will challenge the idea that irradiated foods are not safe.
Answer:
0.1 mol×L
Explanation:
Concentration= MOLES of SOLUTE / Volume of SOLUTION
So all we need to is to calculate the one quantity; Volume of SOLUTION has been specified to be 150 ml
So, MOLES of SOLUTE
x 100 x 10-L = ??mol; this was our starting solution.
And final CONCENTRATION=
0.15 . mol. 5 x 100 x 10-3L/
= 0.15 mol · L-1 150 x 10 3
=0.1 mol · L
