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Paul [167]
3 years ago
6

Reading and Discussing an Article about Making a Homemade Voltaic Cell

Chemistry
1 answer:
sergejj [24]3 years ago
8 0

Answer: The following should be included in your description

• Zinc is the anode, and copper is the cathode

• The lemon flesh and juice provide the salt bridge and electrolyte solution

• Electrons flow from zinc to copper through the external wires

• Electrolytes flow in the lemon. Positive ions (cations) moved toward copper electrodes (cathodes), and negative ions (anions) move toward zinc electrodes (anodes). These balance the charges building up

• Two cells in series provide more energy output than one. The clock may need more energy than can be supplied by one cell

• Batteries do not need external source of reactants, whereas a fuel cell must be supplied with reactants

Explanation: Edg 2021

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Find δs∘ for the reaction between nitrogen gas and hydrogen gas to form ammonia:12n2(g) 32h2(g)→nh3(g)
Dima020 [189]

Nitrogen (N2) and hydrogen (H2) gases react to form ammonia, which requires -99.4 J/K of standard entropy (ΔS°).

What is standard entropy?

The difference between the total standard entropies of the reaction mixture and the summation of the standard entropies of the outputs is the standard entropy change. Each entropy in the balanced equation needs to be compounded by its coefficient, as shown by the letter "n."

Calculation:

Balancing the given reaction following-

1/2 N₂(g) + 3/2 H₂ (g)→ NH₃ (g)

ΔS° = [1 mol x S° (NH₃)g] - [1/2 mol x S° (N₂)g] - [3/2 mol x S°(H₂)g]

Here S° = standard entropy of the system

Insert into the aforementioned equation all the typical entropy values found in the literature:

ΔS° = [1 mol x 192.45 J/mol.K] - [1/2 mol x 191.61 J/mol.K] - [3/2 mol x 130.684 J/mol.K]

⇒ΔS° = - 99.4 J/K

Therefore, the standard entropy, ΔS° is -99.4 J/K.

Learn more about standard entropy here:

brainly.com/question/14356933

#SPJ4

5 0
1 year ago
Arenediazoniums can undergo electrophilic aromatic substitutions with a wide variety of activated aromatic compounds to yield ne
mel-nik [20]
B false
I did this last year and it’s false
4 0
3 years ago
Help please .............​
lapo4ka [179]

Answer:

And what is your question

Explanation:

3 0
4 years ago
A hypothetical element has three main isotopes with mass numbers of 51, 53, and 54. If 15.00% of the isotopes have a mass number
Eva8 [605]

Answer: 53.25

Explanation: Please see attachment for explanation. Thanks.!

5 0
3 years ago
The ph of a 0.55 m aqueous solution of hypobromous acid, hbro, at 25.0°c is 4.48. what is the value of ka for hbro?
elena-14-01-66 [18.8K]

The solution would be like this for this specific problem:

Given:

 

pH of a 0.55 M hypobromous acid (HBrO) at 25.0 °C =  4.48

 

[H+] = 10^-4.48 = 3.31 x 10^-5 M = [BrO-] <span>

Ka = (3.31 x 10^-5)^2 / 0.55 = 2 x 10^-9</span>

 

To add, Hypobromous Acid does not require acid adjustment, which is necessary for chlorine-based product and is stable and effective in pH ranges of 5-9.<span>

</span>Hypobromous Acid combines with organic compounds to form a bromamine. Chlorine also combines with the same organic compounds to form a chloramine. <span>It is also one of the least expensive intervention antimicrobial compounds available.</span>

8 0
4 years ago
Read 2 more answers
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