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harkovskaia [24]
3 years ago
7

30. A solid sample contains only CaCO3, and MgCO3.

Chemistry
1 answer:
lutik1710 [3]3 years ago
8 0

Answer:

Explanation:

Step 1

The mass percent of MgCO3 in the original mixture is calculated as shown,

Step 2

Masses of MgCO3 and CaCO3 is 24g; Moles of carbon dioxide produced from Magnesium carbonate  and Calcium carbonate are.

Step 3

Adding and equating the moles of Carbon dioxide results in,

Step 4

Percent mass of MgCO3 in the sample is calculated as,

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Plate movement is thought to be the result of what ​
Zielflug [23.3K]

Answer: Plate movement is thought to be driven by a combination of the motion of the seafloor away from spreading ridges due to variations in topography and density changes in the crust.

Hope this helps

7 0
3 years ago
pplication)Using multiple models simultaneously: This FNT refers to a processinvolving three moles of a diatomic gas (which beha
Fiesta28 [93]

Complete Question

Questions Diagram is attached below

Answer:

*  W=1142.86Joule

*  Q=997.7J

*  H=2140.5J

Explanation:

From the question we are told that:

Temperature T=337K

Pressure P=(60-55)Pa*10^5

VolumeV=(1.6-1.4)m^3*10^{-3}

Generally the equation for gas Constant is mathematically given by

\frac{P_2}{P_1}=\frac{V_1}{V_2}^n

 \frac{55*10^5}{60*10^5}=\frac{1.4*10^{-3}}{1.6*10^{-3}}^n

 n=0.65

Therefore

Work-done

 W=\int{pdv}

 W=\frac{55*10^5*1.6*10^{-3}*60*10^5*1.4*10^{-3}}{1-0.65}

 W=1142.86Joule

Generally the equation for internal energy is mathematically given by

 Q=mC_vdT\\\\Q=\frac{3*1*3.314*16}{1.4-1}

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Therefore

 H=Q+W

 H=997.7J-11.42.9

 H=2140.5J

5 0
3 years ago
In what two ways can an object possess energy?
-BARSIC- [3]

Explanation:

An object can possess energy in tow ways by it's motion or position

5 0
4 years ago
How many moles of nitrogen are in 2.31L of N2
PtichkaEL [24]

Hey there!

N₂ has a density of 1.25 grams per liter.

We have 2.31 liters of N₂.

2.31 x 1.25 = 2.8875

We have 2.8875 grams of N₂.

Find molar mass of N₂:

N: 2 x 14

------------

         28 g/mol

2.8875 ÷ 28 = 0.10

There is 0.10 mol of nitrogen in 2.31 L of N₂.

Hope this helps!

3 0
3 years ago
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<span>The box with no lightbulb is the control group. The others are treatments. The purpose of a control group is used to increase the validity of the experiment by testing the independent variable to check that it does not influence the results. </span>




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