Answer:
1. Measure the temperature of the boxes and leave them unconnected.
2. Norton reduces his circuit down to a single resistance in parallel with a constant current source. A real-life Norton equivalent circuit would be continuously wasting power (as heat) as the current source dumps energy into the resistor, even when externally unconnected, while a Thevenin equivalent circuit would sit there doing nothing.
3. The Norton equivalent box would get warm and eventually run out of power. The Thevenin equivalent box would stay at ambient temperature.
Answer:
The solution code is written in Java.
- public class Movie {
- private double [][] seats = new double[5][5];
- private double totalSales;
-
- public Movie(){
-
- for(int i= 0; i < this.seats.length; i++){
- for(int j = 0; j < this.seats[i].length; j++){
- this.seats[i][j] = 12;
- }
- }
-
- this.totalSales = 0;
- }
-
- public boolean bookSeat(int i, int j)
- {
- if(this.seats[i][j] != 0){
- this.totalSales += this.seats[i][j];
- this.seats[i][j] = 0;
- return true;
- }else{
- return false;
- }
-
- }
- }
Explanation:
The method, bookSeat(), as required by the question is presented from Line 16 - 26 as part of the public method in a class <em>Movie</em>. This method take row,<em> i</em>, and column,<em> j</em>, as input.
By presuming the seats is an two-dimensional array with all its elements are initialized 12 (Line 7 - 10). This means we presume the movie ticket price for all the seats are $12, for simplicity.
When the<em> bookSeat() </em>method is invoked, it will check if the current price of seats at row-i and column-i is 0. If not, the current price, will be added to the <em>totalSales </em>(Line 19)<em> </em>and then set the price to 0 (Line 20) and return <em>true</em> since the ticket is successfully sold (Line 21). If it has already been sold, return <em>false</em> (Line 23).
Answer:
Explanation:
Given that
L= 50 m
Pressure drop = 130 KPa
For Copper tube is 3/4 standard type K drawn tube
Outside diameter=22.22 mm
Inside diameter=18.92 mm
Dynamic viscosity for kerosene
Pressure difference given as
Where
L is length of tube
μ is dynamic viscosity
Q is volume flow rate
d is inner diameter of tube
ΔP is pressure drop
Now by putting the values
So flow rate is
Answer:
the curve will flatten due to the supply and demand theory.
To be honest theres a lot...
