Answer:
Distributes a floor load or weight
Explanation:
Answer:
Explanation:
From the given question:
Using the distortion energy theory to determine the factors of safety FOS can be expressed by the relation:

where; syt = strength in tension and compression = 350 MPa
The maximum shear stress theory can be expressed as:

where;

a. Using distortion - energy theory formula:



FOS = 2.183
USing the maximum-shear stress theory;




FOS = 1.977
b. σx = 110 MPa, σy = 100 MPa
Using distortion - energy theory formula:




FOS =3.322
USing the maximum-shear stress theory;



FOS = 350/2×25
FOS = 350/50
FOS = 70
c. σx = 90 MPa, σy = 20 MPa, τxy =−20 MPa
Using distortion- energy theory formula:



FOS = 350/88.88
FOS = 3.939
USing the maximum-shear stress theory;





FOS = 4.341
Answer:
work done = 48.88 ×
J
Explanation:
given data
mass = 100 kN
velocity = 310 m/s
time = 30 min = 1800 s
drag force = 12 kN
descends = 2200 m
to find out
work done by the shuttle engine
solution
we know that work done here is
work done = accelerating work - drag work - descending work
put here all value
work done = ( mass ×velocity ×time - force ×velocity ×time - mass ×descends ) 10³ J
work done = ( 100 × 310 × 1800 - 12×310 ×1800 - 100 × 2200 ) 10³ J
work done = 48.88 ×
J
To get rockets into orbit, they need much more thrust than the amount that will get them up to the required altitude. They also need sufficient thrust to allow them to travel with very high orbital speed. ... If speed is less than this, an object will fall back to the Earth
Answer:
a) 5.2 kPa
b) 49.3%
Explanation:
Given data:
Thermal efficiency ( л ) = 56.9% = 0.569
minimum pressure ( P1 ) = 100 kpa
<u>a) Determine the pressure at inlet to expansion process</u>
P2 = ?
r = 1.4
efficiency = 1 - [ 1 / (rp)
]
0.569 = 1 - [ 1 / (rp)^0.4/1.4
1 - 0.569 = 1 / (rp)^0.285
∴ (rp)^0.285 = 0.431
rp = 0.0522
note : rp = P2 / P1
therefore P2 = rp * P1 = 0.0522 * 100 kpa
= 5.2 kPa
b) Thermal efficiency
Л = 1 - [ 1 / ( 10.9 )^0.285 ]
= 0.493 = 49.3%