Answer:
thanks thanks thanks thanks
Explanation:
The modern hydraulic lifts make use of biodegradable fluid to transmit hydraulic power
<em>Question: The options are left out in the question. The details and facts about the modern hydraulic lift are presented here</em>
<em />
Details about the modern hydraulic lifts include;
The development of the modern hydraulic occurred in the Industrial Revolution to perform task done previously by steam powered elevators
The power of the hydraulic lift come from the hydraulic cylinder known as the actuator, which in turn is powered by pressurized hydraulic fluid such as oil
The hydraulic fluid is pushed by a piston rod through which energy is capable of being transferred, such that the applied force is multiplied, to provide more power for lifting
<u>Facts about the modern hydraulic lifts include;</u>
- The dry motor in the modern hydraulic lift is more efficient and consumes 20% less energy
- It comprises of valves that are controlled electronically such that the response is much rapid and the energy consumption is reduced by a further 20%
- The cars used in the modern lift are lighter, as well as the slings, which reduces the power usage by 20%
- It makes use of chemicals which are environmentally friendly as hydraulic fluid
- The flash point of the fluid used is higher, as well as it posses 50% lower compressibility as well elasticity
Learn more here:
brainly.com/question/16942803
Answer:
Quantum
Explanation:
Appearance of energy particles from any where as allowed by uncertainty principle.
Answer:
y = -1/24 x³ + 5/12 x² − 35/24 x + 25/12
Explanation:
A cubic has the form:
y = ax³ + bx² + cx + d
Given four points, we can write a system of equations:
1 = a + b + c + d
1/2 = 8a + 4b + 2c + d
1/3 = 27a + 9b + 3c + d
1/4 = 64a + 16b + 4c + d
Solving this algebraically would be time-consuming, but we can use matrices to make it easy.
![\left[\begin{array}{cccc}1&1&1&1\\8&4&2&1\\27&9&3&1\\64&16&4&1\end{array}\right]\left[\begin{array}{cccc}a\\b\\c\\d\end{array}\right]=\left[\begin{array}{cccc}1\\1/2\\1/3\\1/4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%261%261%261%5C%5C8%264%262%261%5C%5C27%269%263%261%5C%5C64%2616%264%261%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7Da%5C%5Cb%5C%5Cc%5C%5Cd%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%5C%5C1%2F2%5C%5C1%2F3%5C%5C1%2F4%5Cend%7Barray%7D%5Cright%5D)
First, we find the inverse of the coefficient matrix. This is messy to do by hand, so let's use a calculator:
![\left[\begin{array}{cccc}1&1&1&1\\8&4&2&1\\27&9&3&1\\64&16&4&1\end{array}\right] ^{-1} =-\frac{1}{12}\left[\begin{array}{cccc}2&-6&6&-2\\-18&48&-42&12\\52&-114&84&-22\\-48&72&-48&12\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%261%261%261%5C%5C8%264%262%261%5C%5C27%269%263%261%5C%5C64%2616%264%261%5Cend%7Barray%7D%5Cright%5D%20%5E%7B-1%7D%20%3D-%5Cfrac%7B1%7D%7B12%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D2%26-6%266%26-2%5C%5C-18%2648%26-42%2612%5C%5C52%26-114%2684%26-22%5C%5C-48%2672%26-48%2612%5Cend%7Barray%7D%5Cright%5D)
Now we multiply by the solution matrix (again using a calculator):
![-\frac{1}{12} \left[\begin{array}{cccc}2&-6&6&-2\\-18&48&-42&12\\52&-114&84&-22\\-48&72&-48&12\end{array}\right]\left[\begin{array}{cccc}1\\1/2\\1/3\\1/4\end{array}\right] =\left[\begin{array}{cccc}-1/24\\5/12\\-35/24\\25/12\end{array}\right]](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B12%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D2%26-6%266%26-2%5C%5C-18%2648%26-42%2612%5C%5C52%26-114%2684%26-22%5C%5C-48%2672%26-48%2612%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%5C%5C1%2F2%5C%5C1%2F3%5C%5C1%2F4%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-1%2F24%5C%5C5%2F12%5C%5C-35%2F24%5C%5C25%2F12%5Cend%7Barray%7D%5Cright%5D)
So the cubic is:
y = -1/24 x³ + 5/12 x² − 35/24 x + 25/12
Answer:
V = 6.33 m/s
Explanation:
Given:
- The length of the wire L = 0.02 m
- The diameter of the wire D = 0.0005 m
- The calibration expression V = 0.0000625*h^2
- Environment temperature T_inf = 298 K
- Surface temperature T_s = 348 K
- The voltage drop dV = 5 V
- The electric current I = 0.1 A
Find:
- the velocity of Air
Solution:
- Calculate the surface area of the wire:
A = pi*D*L
A = pi*(0.0005)*(0.02) = 0.00003142 m^2
- The rate of energy in the wire P:
P = I*dV = 0.1*5 = 0.5 W
- Apply Newton's Law of Cooling:
P = h*A*(T_s - T_inf)
h = P /A*(T_s - T_inf)
Plug in the values:
h= 0.5/ 0.00003142*(348 - 298)
h = 318.27 W /m^2K
- Using the calibration relationship given, compute the velocity of air:
V = 6.25*10^-5 * h^2
V = 6.25*10^-5 * (318.27)^2
V = 6.33 m/s
