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AnnZ [28]
3 years ago
11

To what category of elements does an element belong if it's a poor conductor of electricity

Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
7 0

Answer:

I would assume NON-METALS

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What is the volume (in cubic inches) of 3.6 lb of titanium? The density of titanium is 4.51 g/cm3
SashulF [63]
Answer: 362,07 cm3
To answer this question you need to convert the lb into gram first. One lb equal to 453.592g, so: 3.6lb x 453.592gram/lb= 1632.9312gram. 
Now we have mass(1632.9312g), density (4.51g/cm3). Volume is mass divided by density. The equation would be:

Volume= mass/density
Volume = 1632.9312gram / (4.51g/cm3)= 362,07 cm3
6 0
3 years ago
Can you identify 2 characteristics of combustion reactions?
monitta
An element or compound will react with oxygen and will produce carbon dioxide, water, and sometimes carbon (if it is an incomplete combustion).
4 0
3 years ago
What is the affect of attraction or pull gravity between the sun and moon
REY [17]
I think the sun would suck in the moon
4 0
3 years ago
Water molecules stick together by a force called?
patriot [66]

Answer:

Cohesion

Explanation:

Depending on how attracted molecules of the same substance are to one another, the substance will be more or less cohesive. Hydrogen bonds cause water to be exceptionally attracted to each other. Therefore, water is very cohesive.

8 0
3 years ago
Read 2 more answers
The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant. 2A(g)
monitta

Answer:

The value of the missing equilibrium constant ( of the first equation) is 1.72

Explanation:

First equation: 2A + B ↔ A2B   Kc = TO BE DETERMINED

 ⇒ The equilibrium expression for this equation is written as: [A2B]/[A]²[B]

Second equation: A2B + B ↔ A2B2   Kc= 16.4

⇒ The equilibrium expression is written as: [A2B2]/[A2B][B]

Third equation:  2A + 2B ↔ A2B2     Kc = 28.2

⇒ The equilibrium expression is written as: [A2B2]/ [A]²[B]²

If we add the first to the second equation

2A + B + B ↔ A2B2   the equilibrium constant Kc will be X(16.4)

But the sum of these 2 equations, is the same as the third equation ( 2A + 2B ↔ A2B2)   with Kc = 28.2

So this means: 28.2 = X(16.4)

or X = 28.2/16.4

X = 1.72

with X = Kc of the first equation

The value of the missing equilibrium constant ( of the first equation) is 1.72

7 0
3 years ago
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