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3 years ago

Identify the limiting reactant when 9.65-g H2SO4 reacts with 6.10-g of NaOH. I need help

Chemistry

1 answer:

12345 [234]3 years ago

8 0

The equation is H2SO4 + 2NaOH = 2H2O + Na2SO4, Also, what is the theoretical yield of Na2SO4 in grams?

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What element has 1 energy level and 2 valence electrons

Anvisha [2.4K]

Answer: Hydrogen and helium

Explanation:

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MrMuchimi

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3 years ago

When cyclopentane undergo free-radical substitution with bromine (Br2 /Heat) the product:

Artemon [7]

Explanation:

b. Bromo cyclopentane + HBr

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3 years ago

A mixture of N2, O2, and Ar has mole fractions of 0.25, 0.65, and 0.10, respectively. What is the pressure of N2 if the total pr

s344n2d4d5 [400]

Answer:

Partial pressure of nitrogen gas is 0.98 bar.

Explanation:

According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gases.

$P=p_{N_2}+p_{O_2}+p_{Ar}$

$p_{N_2}=P\times \chi_{N_2}$

$p_{O_2}=P\times \chi_{O_2}$

$p_{Ar}=P\times \chi_{Ar}$

where,

$P$ = total pressure = 3.9 bar

$p_{N_2}$ = partial pressure of nitrogen gas

$p_{O_2}$ = partial pressure of oxygen gas

$p_{Ar}$ = partial pressure of argon gases

$\chi_{N_2}$ = Mole fraction of nitrogen gas = 0.25

$\chi_{O_2}$ = Mole fraction of oxygen gas = 0.65

$\chi_{Ar}$ = Mole fraction of argon gases = 0.10

Partial pressure of nitrogen gas :

$p_{N_2}=P\times \chi_{N_2}=3.9 bar\times 0.25 =0.98 bar$

Partial pressure of oxygen gas :

$p_{N_2}=P\times \chi_{O_2}=3.9 bar\times 0.65=2.54 bar$

Partial pressure of argon gas :

$p_{N_2}=P\times \chi_{Ar}=3.9 bar\times 0.10=0.39 bar$

7 0

4 years ago

Which of the following has the lowest Ka?a. carbonic acid b. dihydrogen phosphate c. phosphoric acid d. bicarbonate

Naya [18.7K]

Explanation:

A compound or molecule which will have least dissociation and that is not able to given hydrogen ion easily upon dissociation will also have a low value of $K_{a}$ .

Dissociation of the given compounds or species will be as follows.

$H_{2}CO_{3} \rightleftharpoons H^{+} + HCO^{-}_{3}$

$H_{2}PO^{-}_{4} \rightleftharpoons H^{+} + HPO^{-}_{4}$

$H_{3}PO_{4} \rightleftharpoons H_{+} + H_{2}PO^{-}_{4}$

As, chemical formula of bicarbonate is $HCO^{-}_{3}$ and due to the presence of a negative charge it is difficult to lose a positively charged hydrogen ion. This is because oppositely charged ions will be bonded by strong force of attraction.

Hence, it will not easily lose a hydrogen ion due to which bicarbonate has the lowest $K_{a}$ .

Thus, we can conclude that out of the given species bicarbonate has the lowest $K_{a}$ .

7 0

3 years ago