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3 years ago

Identify the limiting reactant when 9.65-g H2SO4 reacts with 6.10-g of NaOH. I need help

Chemistry

1 answer:

12345 [234]3 years ago

8 0

The equation is H2SO4 + 2NaOH = 2H2O + Na2SO4, Also, what is the theoretical yield of Na2SO4 in grams?

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Either B or C. Composition or the Distance from the Earth.

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3 years ago

Has highest melting point of two bonds

Liono4ka [1.6K]

Answer:

Ionic compounds

Explanation:

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3 years ago

Vinegar is classified as a base, acid, or is it neutral ?

Scrat [10]

Answer:

Vinegar is acidic => acetic acid (HC₂H₃O₂)

Explanation:

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3 years ago

A student titrates 10.00 milliliters of hydrochloric acid of unknown molarity with 1.000 m naoh. it takes 21.17 milliliters of b

Dima020 [189]

Mole ratio for the reaction is 1:1
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4 0

3 years ago

What is the volume, in milliliters, occupied by 30.07 g of an object of density equal to

den301095 [7]

Answer:

$\boxed {\tt 20.317567567568 \ mL}$

Explanation:

The density formula is:

$d=\frac{m}{v}$

Let's rearrange the formula for $v$ . the volume. Multiply both sides by $v$ , then divide by $d$ .

$d*v=\frac{m}{v}*v$

$d*v=m$

$\frac{d*v}{d}=\frac{m}{d}$

$v=\frac{m}{d}$

The volume can be found by dividing the mass by the density. The mass of the object is 30.07 grams and the density is 1.48 grams per milliliter.

$m= 30.07 \ g\\d= 1.48 \ g/mL$

$v=\frac{30.07 \ g}{1.48 \ g/mL}$

Divide. Note, when dividing, the grams, or $g$ will cancel out.

$v= \frac{30.07}{1.48 \ mL}$

$v=20.317567567568 \ mL$

The volume of the object is 20.317567567568 milliliters.

3 0

3 years ago