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antoniya [11.8K]
4 years ago
7

Eric's father asked an engineer to survey the field behind their house. He wanted to plant some apple and pear trees there. Acco

rding to the survey, the field is 38 meters (m) long and 17 meters (m) wide. What is the perimeter of the field in centimeters?
Chemistry
1 answer:
scoray [572]4 years ago
5 0

Answer:

P=110 m

Explanation:

Length of the field is 38 m

Breadth of the field is 17 m

We need to find the perimeter of this field. It is in the form of a rectangle. The perimeter of a rectangle is given by :

P=2(l+b)

P=2(38+17)

P=110 m

So, the perimeter of this field is 110 m.

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Calculate the mass percent of HOCH 2CH 2OH in a solution made by dissolving 3.2 g of HOCH 2CH 2OH in 43.5g of water.
grin007 [14]

Answer:

\%m/m=6.85\%

Explanation:

Hello,

In this case, we are asked to compute the by mass percent for the given 3.2 g of ethylene glycol in 43.5 g of water. In such a way, since the by mass percent is computed as follows:

\%m/m=\frac{m_{solute}}{m_{solute}+m_{solvent}} *100\%

Whereas the solute is the ethylene glycol and the solvent the water, therefore we obtain:

\%m/m=\frac{3.2g}{3.2g+43.5g} *100\%\\\\\%m/m=6.85\%

Best regards.

5 0
3 years ago
Which type of reaction occurs when 50mL quantities of 1 M Ba(OH)2 (aq) and H2SO4 (aq) are combined
iragen [17]
Double replacement.

Ba(OH)2 + H2SO4 ====> 2H2O + BaSO4
5 0
4 years ago
A mixture of gaseous CO and H2, called synthesis gas, is used commercially to prepare methanol (CH3OH), a compound considered an
mr_godi [17]

Answer : The value of equilibrium constant (K) is, 424.3

Explanation :  Given,

Concentration of H_2 at equilibrium = 0.067 mol

Concentration of CO at equilibrium = 0.021 mol

Concentration of CH_3OH at equilibrium = 0.040 mol

The given chemical reaction is:

CO+2H_2\rightarrow CH_3OH

The expression for equilibrium constant is:

K_c=\frac{[CH_3OH]}{[CO][H_2]^2}

Now put all the given values in this expression, we get:

K_c=\frac{(0.040)}{(0.021)\times (0.067)^2}

K_c=424.3

Thus, the value of equilibrium constant (K) is, 424.3

4 0
3 years ago
The partial pressure of CO2 gas in a bottle of carbonated water is 4.60 atm at 25 ºC. How much CO2 gas (in g) will be released f
frutty [35]

If the partial pressure of CO₂ in a bottle of carbonated water decreases from 4.60 atm to 1.28 atm, the mass of CO₂ released is 0.265 g.

The partial pressure of CO₂ gas in a bottle of carbonated water is 4.60 atm at 25 ºC. We can calculate the concentration of CO₂ using Henry's law.

C = k \times P = \frac{1.65 \times 10^{-3} M }{atm}  \times 4.60 atm = 7.59 \times 10^{-3} M

We can calculate the mass of CO₂ in 1.1 L considering its molar mass is 44.01 g/mol.

\frac{7.59 \times 10^{-3} mol}{L} \times  1.1 L \times \frac{44.01 g}{mol}  = 0.367 g

Now, we will repeat the same procedure for a partial pressure of 1.28 atm.

C = k \times P = \frac{1.65 \times 10^{-3} M }{atm}  \times 1.28 atm = 2.11 \times 10^{-3} M

\frac{2.11 \times 10^{-3} mol}{L} \times  1.1 L \times \frac{44.01 g}{mol}  = 0.102 g

The mass of CO₂ released will be equal to the difference in the masses at the different pressures.

m = 0.367 g - 0.102 g = 0.265 g

If the partial pressure of CO₂ in a bottle of carbonated water decreases from 4.60 atm to 1.28 atm, the mass of CO₂ released is 0.265 g.

Learn more: brainly.com/question/18987224

<em>The partial pressure of CO₂ gas in a bottle of carbonated water is 4.60 atm at 25 ºC. How much CO₂ gas (in g) will be released from 1.1 L of the carbonated water when the partial pressure of CO2 is lowered to 1.28 atm? At 25 ºC, the Henry’s law constant for CO₂ dissolved in water is 1.65 x 10⁻³ M/atm, and the density of water is 1.0 g/cm³.</em>

5 0
3 years ago
Overall do you think photosynthesis is endothermic or exothermic
blondinia [14]

Answer:

Endothermic hope that helps

Explanation:

6 0
3 years ago
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