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Assoli18 [71]
2 years ago
13

The time delay between transmission and the arrival of the reflected wave of a signal using ultrasound traveling through a piece

of fat tissue was 0.13 ms. At what depth did this reflection occur? (The average propagation speed for sound in body tissue is 1540 m/s)
Physics
1 answer:
Brilliant_brown [7]2 years ago
8 0

Answer:

10.01 cm

Explanation:

Given that,

The time delay between transmission and the arrival of the reflected wave of a signal using ultrasound traveling through a piece of fat tissue was 0.13 ms.

The average propagation speed for sound in body tissue is 1540 m/s.

We need to find the depth when the reflection occur. We know that, the distance is double when transmitting and arriving. So,

v=\dfrac{2d}{t}\\\\d=\dfrac{vt}{2}\\\\d=\dfrac{1540\times 0.13\times 10^{-3}}{2}\\\\d= $$0.1001\ m

or

d = 10.01 cm

So, the reflection will occur at 10.01 cm.

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120 m/s

Explanation:

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4 0
2 years ago
#3: a container has the dimensions of 30 cm x 50 mm x 0.2 m. the density of its contents is 2.5 g/cm3. what is the mass of the s
WARRIOR [948]
Good afternoon!

We calculate the volume of the container in cm³. To do that, we must put the units in cm:

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50 mm → 5 cm
0.2 m → 20 cm

The volume is:

V = 30 . 5 . 20

V = 3000 cm³

Now, we calculate the mas with the formula:

m = dV

m = 2.5 · 3000

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Dividing by 1000, we have the mass in kg:


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3 years ago
Read 2 more answers
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