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hichkok12 [17]
3 years ago
15

A 12 kg hanging sculpture is suspended by a 80-cm-long, 6.0 g steel wire. When the wind blows hard, the wire hums at its fundame

ntal frequency. What is the frequency of the hum
Physics
1 answer:
Deffense [45]3 years ago
4 0

Answer:

F=78.3hz

Explanation:

From the question we are told that:

Mass m=12

Length l=80cm=0.8m

Linear density \mu= 6.0g

Generally the equation for Frequency is mathematically given by

 F=\frac{1}{2l}\sqrt{\frac{T}{K}}

 F=\frac{1}{2(0.8)}\sqrt{\frac{12*9.8*0.8}{6*10^{-3}}}

 F=78.3hz

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I just need number 2
il63 [147K]

We will apply the conservation of linear momentum to answer this question.

Whenever there is an interaction between any number of objects, the total momentum before is the same as the total momentum after. For simplicity's sake we mostly use this equation to keep track of the momenta of two objects before and after a collision:

m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'

Note that v₁ and v₁' is the velocity of m₁ before and after the collision.

Let's choose m₁ and v₁ to represent the bullet's mass and velocity.

m₂ and v₂ represents the wood block's mass and velocity.

The bullet and wood will stick together after the collision, so their final velocities will be the same. v₁' = v₂'. We can simplify the equation by replacing these terms with a single term v'

m₁v₁ + m₂v₂ = m₁v' + m₂v'

m₁v₁ + m₂v₂ = (m₁+m₂)v'

Let's assume the wood block is initially at rest, so v₂ is 0. We can use this to further simplify the equation.

m₁v₁ = (m₁+m₂)v'

Here are the given values:

m₁ = 0.005kg

v₁ = 500m/s

m₂ = 5kg

Plug in the values and solve for v'

0.005×500 = (0.005+5)v'

v' = 0.4995m/s

v' ≅ 0.5m/s

4 0
2 years ago
1) Think of planting a tree. You dig the hole, put it in, and fill it back in. Next,
pogonyaev

Answer:

at the top of the tree I hope it will help you please follow me

6 0
2 years ago
A 10.00 kg mass is moving to the right with a velocity of 14.0 m/s. A 12.0 kg mass is moving to the left with a velocity of 8.00
Basile [38]

Answer:

2 m/s

Explanation:

From the conservation of momentum, the initial momentum of the system must be equal to the final momentum of the system.

Let the 10.00 kg mass be m_1 and the 12.0 kg mass be m_2. When they collide and stick, they have a combined mass of m_1+m_2.

Momentum is given by p=mv. Set up the following equation:

\displaystyle m_1v_1+m_2v_2=(m_1+m_2)v_f, where v_f is the desired final velocity of the masses.

Call the right direction positive. To indicate the 12.0 kg object is travelling left, its velocity should be substitute as -8.00 m/s.

Solving yields:

10\cdot 14 + 12\cdot (-8)=(10+12)v_f\\\implies v_f=\boxed{2 \text{ m/s}}

4 0
2 years ago
What's the weight of a 30x30x50 cm body with the density of 1.8/cm cube?
grin007 [14]

Answer:

The weight of the body, W = 793.8 m/s²

Explanation:

Given,

The volume of the body, v = 45,000 cm³

The density of the body, ρ = 1.8 g/cm³

The mass of the body is given by the formula,

                                  m = ρ x v

                                      = 1.8 g/cm³ x 45,000 cm³

                                      = 81,000 g

Hence, the mass of the body is m = 81 kg

The weight of the body,

                                           W = m x g

                                                = 81 kg x 9.8 m/s²

                                                = 793.8 m/s²

Hence, the weight of the body, W = 793.8 m/s²

3 0
2 years ago
A tennis ball is thrown straight up into the air with an initial velocity of 38 m/s.
geniusboy [140]

Answer:

a) 3.9s

b)74m

Explanation:

a) v=u+at

0=38+(-9.8)t

-38=-9.8t

t=-38/-9.8

t=3.877s

t=3.9s

b) s=ut+1/2at²

s=(38×3.9)+1/2(-9.8×3.9²)

s=148.2 -74.529

s=73.671

s=74m

8 0
2 years ago
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