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Reil [10]
4 years ago
10

Are teen courts a good idea

Engineering
1 answer:
Zolol [24]4 years ago
6 0

Idea about teen courts is given below

Explanation:

1.Teen courts are spreading rapidly across the United States. Many people view them as a cost-effective alternative to traditional juvenile court for some young offenders.

2.Teen courts are generally used for  younger juveniles (ages 10 to 15), those  with no prior arrest records, and those  charged with less serious law violations (e.g., shoplifting, vandalism, and disorderly conduct). Typically, young offenders are offered teen court as a voluntary  alternative in lieu of more formal handling  by the traditional juvenile justice system

3.Teen courts differ from other juvenile justice programs because  young people rather than adults determine the disposition, given a broad array  of sentencing options made available by  adults overseeing the program.

4.Teen  court defendants may go through an intake process, a preliminary review of charges, a court hearing, and sentencing, as in a regular juvenile court. In a teen  court, however, other young people are  responsible for much of the process.  Charges may be presented to the court by  a 15-year-old “prosecutor.” Defendants  may be represented by a 16-year-old “defense attorney.” Other youth may serve as  jurors, court clerks, and bailiffs.

5.In some  teen courts, a youth “judge” (or panel of  youth judges) may choose the best disposition or sanction for each case. In a few  teen courts, youth even determine  whether the facts in a case have been  proven by the prosecutor (similar to a  finding of guilt).

6.Adults are also involved in teen courts.  They often administer the programs, and  they are usually responsible for essential  functions such as budgeting, planning,  and personnel.

7.Teen courts are seen as a  potentially effective alternative to traditional juvenile courts staffed with paid  professionals such as lawyers, judges, and  probation officers. Teen court advocates  also point out that the benefits extend beyond defendants. Teen courts may benefit  the volunteer youth attorneys and judges,  who probably learn more about the legal  system than they ever could in a classroom. The presence of a teen court may  also encourage the entire community to  take a more active role in responding to  juvenile crime. Teen courts offer at least  four potential benefits:

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While walking across campus one windy day, an engineering student speculates about using an umbrella as a "sail" to propel a bic
makvit [3.9K]

Answer:

Given data:\\While walking across campus one windy day\\Frontal area, \(A=0.3 m ^{2}\)\\Wind speed \(V=24 Km / hr\)\\The drag coefficient \(C_{D, b}=1.2\)\\The combined mass \(m=75 kg\)\\Umbrella diameter, \(D=1.22 m\)\\Velocity of wind \(V=24 \frac{ km }{ hr }\)\\The rolling resistance \(C_{R}=0.75 \%\)

Solution:

Note: Refer the diagram

Basic equation:\\'s law of motion: \(\sum F_{x}=m a_{x}\)\\Lift coefficient, \(C_{L}=\frac{F_{L}}{\frac{1}{2} \rho V^{2} A_{p}}\)\\Drag coefficient, \(C_{D}=\frac{F_{D}}{\frac{1}{2} \rho V^{2} A_{p}}\)

From force balance equation:\\\(\sum F_{x}=F_{D}-F_{R}=0\)\\But \(F_{D}=\left(C_{D, \alpha} A_{u}+C_{D, B} A_{b}\right) \frac{1}{2} \rho\left(V_{\nu}-V_{b}\right)^{2}\)\(F_{R}=C_{R} m g\)\\Area of the Umbrella \(A_{u}=\frac{\pi D_{u}^{2}}{4}\)\(A_{x}=\frac{\pi \times 1.22^{2}}{4} m ^{2}\)\(A_{v}=1.17 m ^{2}\)

Drag coefficient data for selected objects table at

Hemisphere (open end facing flow), C_{D, x}=1.42

Substituting all parameters,

\begin{aligned}&F_{R}=0.0075 \times 75 \times 9.81\\&F_{R}=5.52 N\end{aligned}

Then,

\begin{aligned}&V_{b}=V_{w}-\left[\frac{2 F_{R}}{\rho\left(C_{D, w} A_{w}+C_{D, B} A_{b}\right)}\right]^{\frac{1}{2}} \dots\\&V_{w}=24 \times 1000 \times \frac{1}{3600}\\&V_{w}=6.67 \frac{ m }{ s }\end{aligned}

And the equation becomes,

\begin{aligned}&V_{b}=6.67-\left[\frac{2 \times 5.52}{1.23(1.42 \times 1.17+1.2 \times 0.3)}\right]^{\frac{1}{2}}\\&V_{b}=6.67-2.11\\&V_{b}=4.56 \frac{ m }{ s }\end{aligned}

Thus the floyds travels at 68.3^{\circ}wind speed.

7 0
4 years ago
A company, studying the relation between job satisfaction and length of service of employees, classified employees into three le
Wewaii [24]

Answer:

Below see details

Explanation:

A) It is attached. Please see the picture

B) First to calculate the overall mean,  

μ=65∗25/75+80∗25/75+95∗25/75  

μ=65∗25/75+80∗25/75+95∗25/75 = 80

Next to calculate E(MSTR) = σ2+(1/r−1) ∑ni(μi−μ)^2 = 5634

And E(MSE) = σ^2= 9

C) Yes, it is substantially large than E(MSE) in this case.

D) If we sampled 25 employees from each group, we are likely to get a F statistics to indicate differences of job satisfactions among three types of length of service of employees.

3 0
3 years ago
How many kg / day of NaOH must be added to neutralize a waste stream generated by an industry producing 90,800 kg / day of sulfu
hram777 [196]

Answer:

74.12kg/day

Explanation:

Equation of reaction for the neutralization reaction of sodium hydroxide and sulfuric acid: 2NaOH + H2SO4 yields Na2SO4 + 2H2O

Mass of sulfuric acid produced per day = 90,800kg

Percentage of sulfuric acid in wastewater = 0.1%

Mass of sulfuric acid that ends up in wastewater per day = 0.1/100 × 90,800 = 90.8kg

From the equation of reaction, 2 moles of NaOH (80kg of NaOH) is required to neutralize 1 mole of H2SO4 (98kg of H2SO4)

80kg of NaOH is required to neutralize 98kg of sulfuric acid

90.8kg of sulfuric acid would be neutralized by (90.8×80)/98kg of NaOH = 74.14kg/day of NaOH

7 0
3 years ago
Read 2 more answers
Suppose that you are working in a home that has a 15kw oven that operates on 240 V, The oven is on a branch circuit by itself. W
krok68 [10]

Explanation:

please see it my work solution

7 0
3 years ago
A full journal bearing has a shaft diameter of 3.000 in with a unilateral tolerance of -0.0004 in. The l/d ratio is unity. The b
sashaice [31]

Answer:

i) 154°F

ii) 0.0114 mm

iii) 0.075 btu/s

iv) 0.080 in^3/s

Explanation:

<u>i)Determine the average film Temperature </u>

( from Viscosity-temperature chart in US customary units for SAE10 )

at Temp =  154°F

absolute viscosity = 4.25 rev

and ΔT = 2 ( 154 - operating temp ) = 28°F

where : operating temp = 140°F as given in question

also from the chart applying Raimondi and Boyd boundary conditions

ΔT = 29°F  hence we can pick 154°F as the average film temperature

<u>ii) Calculate the minimum film thickness</u>

Cmin = Bore diameter - Journal shaft diameter / 2

         = 3.003 - 3 / 2 = 0.0015 in

Given that : h₀ / Cmin = 0.76

there h₀ = 0.0015 * 0.76 = 0.0114 mm

<u>iii)Determine the heat loss rate </u>

Also known as power loss ratio ( H ) = ( 2π*w*f*r*N ) / ( 778 *12 )

( 2π * 0.0132 * 675 * 1.5 * 10 ) / ( 9336 )

Heat loss rate = 0.075 btu/s

<u>iv)Calculate lubricant side-flow rate for minimum clearance assembly </u>

Side flow rate = 0.315 * Total volume flow rate

                       = 0.315 * ( 3.8 * 1.5 * 0.0015 * 10 * 3 )

                      = 0.080 in^3/s.

6 0
3 years ago
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