Question

Suppose you are pushing on a crate across a floor as shown below. Assume the friction force is 47.0 N. How much time will it take for the crate to reach 6.0 m/s if it started from rest? Assume the weight of the crate is 2058 N. (250 N force applied)
(Question is no longer a priority but i’d like to know the answer and how it’s found) pls don’t scam i’m serious man i need to know

Answer 1

Answer:

6.2 seconds

Explanation:

Using Newton's second law, ∑F=ma, we know the net force acting on the object is Force applied-Force of friction. The net force is 203 N. Newton's second law requires the mass of an object, not the weight force, so we will have to calculate the mass. We know that m*g=weight force,  in this case, solve for the mass and you will get 210 kg. Now that we have the value of the net force and the mass, we can solve for acceleration. $\frac{F}{m}=a$=0.967 m/s^2. Now, since we have the acceleration, initial velocity(0 m/s), and the final velocity (6m/s) we will use these to solve for time using the kinematic equation Vf=Vi + at. Plug in the values we know and solve for time and you will get 6.2 seconds