Answer:
5.25 g NaF
Step-by-step explanation:
We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 41.99
Na₂SiO₃ + 8HF ⟶ H₂SiF₆ + 2 NaF + 3H₂O
n/mol: 8
(1) Calculate the moles of NaF
The molar ratio is 2 mol NaF/8 mol HF.
Moles of F = 0.500 mol HF × (2 mol Na₂SiO₃/8 mol HF)
Moles of Na₂SiO₃ = 0.125 mol Na₂SiO₃
(2) Calculate the mass of NaF
Mass of NaF = 0.125 mol NaF × (41.99 g Na₂SiO₃/1 mol Na₂SiO₃)
Mass of NaF = 5.25 g NaF
Answer:
Explanation:
According to ideal gas equation:
P = pressure of gas = 0.987 atm
V = Volume of gas = 12 L
n = number of moles = 0.50
R = gas constant =
T =temperature = ?
Thus the temperature of a 0.50 mol sample of a gas at 0.987 atm and a volume of 12 L is
It is colorless and oderless is a physical property by telling what color.
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Answer: The molarity of solution is 3.37 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute = 0.614
= volume of solution in ml = 182 ml
Now put all the given values in the formula of molarity, we get
Therefore, the molarity of solution is 3.37 M