Given:
257J of heat
5500g of mercury
increase by 5.5
degrees Celsius
Required:
Specific heat of
mercury
Solution:
H
= mCpT
257J = (5500g of
mercury) Cp (5.5 degrees Celsius)
Cp = 8.5 x 10^-3
Joules per gram per degree Celsius
Answer:
The answer to your question is below
Explanation:
Data
Substance = NaCl
moles of NaCl = 49
volume = 150 ml
Process
Molarity is a unit of concentration that makes a relation of the moles of a substance and the volume.
Molarity = moles / volume (L)
1.- Convert 150 ml to L
1000 ml ------------------ 1 L
150 ml ----------------- x
x = (150 x 1) / 1000
x = 0.15 L
2.- Substitution
Molarity = 49 / 0.15
Molarity = 326. 7
I have a doubt if the number of moles is 49 moles or 49μmoles
Answer:
<h2>The answer is 4 m/s²</h2>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula

where
a is the acceleration
f is the force
m is the mass
From the question
f = 20 N
m = 5 kg
We have

We have the final answer as
<h3>4 m/s²</h3>
Hope this helps you
Explanation:
It is given that,
The time period of artificial satellite in a circular orbit of radius R is T. The relation between the time period and the radius is given by :

The radius of the orbit in which time period is 8T is R'. So, the relation is given by :



So, the radius of the orbit in which time period is 8T is 4R. Hence, this is the required solution.
The answer should be D all of the above