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3 years ago

12

Boats typically have several metal fittings where ropes can be fastened. What is the name for these metal fittings?

1 answer:

nadezda [96]3 years ago

3 0

The name for these metal fittings is cleats.
Cleats refer to the hooks on your boat and the dock where you can fasten a boat in order to keep it from flowing away while you're not using it. A keel is located under your boat and provides stability; a transom is the part of your boat on the stern where the motor is located; a tiller is a lever you use to turn your boat.

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An element containing a charge.

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Answer:

That means an atom with a neutral charge is one where the number of electrons is equal to the atomic number. Ions are atoms with extra electrons or missing electrons. When you are missing an electron or two, you have a positive charge. When you have an extra electron or two, you have a negative charge

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What name should be used for the ionic compound Co2 (SO4)3?

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Consider the reaction FeO (S) + CO(g) <-----> Fe(s) + CO2(g) for which KP is found to have the following values:

Svetach [21]

Explanation:

$\Delta G^o=-RT\ln K_1$

where,

R = Gas constant = $8.314J/K mol$

T = temperature = $600^oC=[273.15+600]K=873.15 K$

$K_p$ = equilibrium constant at 600°C = 0.900

Putting values in above equation, we get:

$\Delta G^o=-(8.314J/Kmol)\times 873.15 K\times \ln (0.900 )$

$\Delta G^o=764.85 J/mol$

The ΔG° of the reaction at 764.85 J/mol is 764.85 J/mol.

Equilibrium constant at 600°C = $K_1=0.900$

Equilibrium constant at 1000°C = $K_2=0.396$

$T_1=[273.15+600]K=873.15 K$

$T_2=[273.15+1000]K=1273.15 K$

$\ln \frac{K_2}{K_1}=\frac{\Delta H^o}{R}\times [\frac{1}{T_1}-\frac{1}{T_2}]$

$\ln \frac{0.396}{0.900}=\frac{\Delta H^o}{8.314 J/mol K}\times [\frac{1}{873.15 K}-\frac{1}{1273.15 K}]$

$\Delta H^o=-18,969.30 J/mol$

The ΔH° of the reaction at 600 C is -18,969.30 J/mol.

ΔG° = ΔH° - TΔS°

764.85 J/mol = -18,969.30 J/mol - 873.15 K × ΔS°

ΔS° = -22.60 J/K mol

The ΔS° of the reaction at 600 C is -22.60 J/K mol.

$FeO (s) + CO(g)\rightleftharpoons Fe(s) + CO_2(g)$

Partial pressure of carbon dioxide = $p_1=P\times \chi_1$

Partial pressure of carbon monoxide = $p_2=P\times \chi_2$

Where $\chi_1\& \chi_2$ mole fraction of carbon dioxide and carbon monoxide gas.

The expression of $K_p$ is given by:

$K_p=\frac{p_1}{p_2}=\frac{P\times \chi_1}{P\times \chi_2}$

$0.900=\frac{\chi_1}{\chi_2}$

$\chi_1=0.900\times \chi_2$

$\chi_1+\chi_2=1$

$0.9\chi_2+\chi_2=1$

$1.9\chi_2=1$

$\chi_2=\frac{1}{1.9}=0.526$

$\chi_1=1-\chi_2=1-0.526=0.474$

Mole fraction of carbon dioxide at 600°C is 0.474.

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4 years ago

LIST THE FOLLOWING MOLECULES AS EITHER POLAR, IONIC OR NONPOLAR.

mina [271]

Answer:

HCl 1.Polar 2.soluble highly

O2 1.non-polar 2.highly soluble

CaCl2 1.Ionic 2.insoluble

N2 1.non polar 2.soluble highly

C2h6 1.non polar 2.insoluble

KNO3 1.ionic 2.Soluble

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3 years ago