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4 years ago

Boats typically have several metal fittings where ropes can be fastened. What is the name for these metal fittings?

1 answer:

3 0

The name for these metal fittings is cleats.
Cleats refer to the hooks on your boat and the dock where you can fasten a boat in order to keep it from flowing away while you're not using it. A keel is located under your boat and provides stability; a transom is the part of your boat on the stern where the motor is located; a tiller is a lever you use to turn your boat.

You might be interested in

What distinguishes a neutral atom from an ion

Aliun [14]

will they contain the same number of protons as electrons. By the meaning, an "ion" is an electrically charged particle produced by either removing electrons from the neutral atom to give a positive ion or adding electrons to a neutral atom to give a negative" ion".
hope i helped :)

6 0

3 years ago

If 24.1 g of sodium hydroxide react with 22.0 g of hydrochloric acid to form 35.3g

disa [49]

Answer:

10.85 g of H2O.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

NaOH + HCl —> NaCl + H2O

Next, we shall determine the mass of NaOH that reacted and the mass of H2O produced from the balanced equation.

These can be obtained as illustrated below:

Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol

Mass of NaOH from the balanced equation = 1 × 40 = 40 g

Molar mass of H2O = (2×1) + 16 = 2 + 16 = 18 g/mol

Mass of H2O from the balanced equation = 1 × 18 = 18 g

Summary:

From the balanced equation above,

40 g of NaOH reacted to produce 18 g of H2O.

Finally, we shall determine the mass of water, H2O produced from the reaction as follow:

From the balanced equation above,

40 g of NaOH reacted to produce 18 g of H2O.

Therefore, 24.1 g of NaOH will react to produce = (24.1 × 18)/40 = 10.85 g of H2O.

Therefore, 10.85 g of H2O were produced from the reaction.

4 0

4 years ago

How much energy is released by the decay of 3 grams of 230Th in the following reaction 230 Th - 226Ra + "He (230 Th = 229.9837 g

Serhud [2]

Answer: The energy released for the decay of 3 grams of 230-Thorium is $2.728\times 10^{-15}J$

Explanation:

First we have to calculate the mass defect $(\Delta m)$ .

The equation for the alpha decay of thorium nucleus follows:

$_{90}^{230}\textrm{Th}\rightarrow _{88}^{226}\textrm{Ra}+_2^{4}\textrm{He}$

To calculate the mass defect, we use the equation:

Mass defect = Sum of mass of product - Sum of mass of reactant

$\Delta m=(m_{Ra}+m_{He})-(m_{Th})$

$\Delta m=(225.9771+4.008)-(229.9837)=1.4\times 10^{-3}amu=2.324\times 10^{-30}kg$

(Conversion factor: $1amu=1.66\times 10^{-27}kg$ )

To calculate the energy released, we use Einstein equation, which is:

$E=\Delta mc^2$

$E=(2.324\times 10^{-30}kg)\times (3\times 10^8m/s)^2$

$E=2.0916\times 10^{-13}J$

The energy released for 230 grams of decay of thorium is $2.0916\times 10^{-13}J$

We need to calculate the energy released for the decay of 3 grams of thorium. By applying unitary method, we get:

As, 230 grams of Th release energy of = $2.0916\times 10^{-13}J$

Then, 3 grams of Th will release energy of = $\frac{2.0916\times 10^{-13}}{230}\times 3=2.728\times 10^{-15}J$

Hence, the energy released for the decay of 3 grams of 230-Thorium is $2.728\times 10^{-15}J$

5 0

3 years ago

Which substance can be described as a strong base

Shalnov [3]

Lithium Hydroxide or LiOH
Basically anything with a hydroxide (OH) is a strong base

7 0

3 years ago

Read 2 more answers

A student followed the procedure of this experiment to determine the solubility product of zinc(II) iodate, Zn(IO3)2. Solutions

Fed [463]

Answer:

Explanation:

Complete the table below and determine the solubility product constant.

[Zn(NO₃)₂] 0, M Initial 0.226, 0.101 0.0452, 0.0118

[KIO₃] 0, M Titrant 0.200, 0.200, 0.200, 0.200

V₀, mL of Zn(NO₃)₂100.0, 100.0, 100.0, 100.0

V, mL of KIO₃ titrant 12.9, 12.4, 13.0, 18.3

What needs to be determined are the following for each column/sample

V0 + V, mL

[Zn²⁺] + [IO³⁻] ⇄ [Zn²⁺][IO³⁻]2

log [Zn²⁺][IO³⁻]2

$\frac{\sqrt{Zn^{2+}}}{1 + \sqrt{Zn^{2+}}}$

Then there's the determination of Ksp itself

log Ksp = Ksp of Zn(IO3)2 =

Considering this, which of the ion products is closest to Ksp, and why?

Finally, the titration volumes for the first three samples don't vary greatly. However the last sample is considerably larger. Why is this to be expected?

The attached figures shed more light on the solution to this problem

7 0

3 years ago