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vekshin1
3 years ago
13

High-voltage power lines are a familiar sight throughout the country. The aluminum wire used for some of these lines has a cross

-sectional area of 4.8 x 10-4 m2. What is the resistance of 14 kilometers of this wire
Physics
1 answer:
goblinko [34]3 years ago
5 0

Answer:

Explanation:

For resistance of a wire , the formula is as follows

R = ρ L / S

where ρ is specific resistance , L is length and S is cross sectional area

Given L = 14 000 m ,

S = 4.8 x 10⁻⁴ m²

specific resistance of aluminum = 2.8 x 10⁻⁸ ohm-meter

Putting the values in the formula

R = 2.8 x 10⁻⁸ x 14 x 10³ /  (4.8 x 10⁻⁴ )

R = 0.8167 ohm .

= .82 ohm .

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Answer:

Diagram C

Explanation:

We are given  that Sulfur with atomic number 16.

We have to find that which diagram shows the electronic configuration of sulfur.

S=16

Its Diagram C

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You want to move a heavy box with mass 30.0 across a carpeted floor. You pull hard on one of the edges of the box at an angle 30
ivolga24 [154]

Answer:

Explanation:

Check attachment for solution

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3 years ago
A stone of mass 0.2 kg falls with an acceleration of 10.0 m/s. How big is the force that causes this acceleration?
Kobotan [32]

Answer:

\boxed {\boxed {\sf 2 \ Newtons}}

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

F= m \times a

The mass of the stone is 0.2 kilograms and the acceleration is 10.0 meters per square second.

  • m= 0.2 kg
  • a= 10.0 m/s²

Substitute the values into the formula.

F= 0.2 \ kg * 10.0 \ m/s^2

Multiply.

F=2 \ kg*m/s^2

Convert the units.

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F= 2 \ N

The force is <u>2 Newtons.</u>

4 0
3 years ago
The magnetic flux through each turn of a 110-turn coil is given by ΦB = 9.75 ✕ 10−3 sin(ωt), where ω is the angular speed of the
Xelga [282]

Answer:

Explanation:

Given that a coil has a turns of

N = 110 turns

And the flux is given as function of t

ΦB = 9.75 ✕ 10^-3 sin(ωt),

Given that, at an instant the angular velocity is 8.70 ✕ 10² rev/min

ω = 8.70 ✕ 10² rev/min

Converting this to rad/sec

1 rev = 2πrad

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ω = 8.7 × 10² × 2π / 60

ω = 91.11 rad/s

Now, we want to find the induced EMF as a function of time

EMF is given as

ε = —NdΦB/dt

ΦB = 9.75 ✕ 10^-3 sin(ωt),

dΦB/dt = 9.75 × 10^-3•ω Cos(ωt)

So,

ε = —NdΦB/dt

ε = —110 × 9.75 × 10^-3•ω Cos(ωt)

Since ω = 91.11 rad/s

ε = —110 × 9.75 × 10^-3 ×91.11 Cos(91.11t)

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The EMF as a function of time is

ε = —97.71 Cos(91.11t)

Extra

The maximum EMF will be when Cos(91.11t) = -1

Then, maximum emf = 97.71V

8 0
3 years ago
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