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Soloha48 [4]
3 years ago
13

PLEASE HELP

Mathematics
1 answer:
Mumz [18]3 years ago
4 0
The answer should be c .
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Suppose babies born after a gestation period of 32 to 35 weeks have a mean weight of 2700 grams and a standard deviation of 900
rosijanka [135]

Answer:

The 33 week gestation period baby has a zscore of -0.47.

The 41 week gestation period baby has a zscore of -0.94.

The 41 week gestation period baby weighs less relative to the gestation period.

Step-by-step explanation:

Normal model problems can be solved by the zscore formula.

On a normaly distributed set with mean \mu and standard deviation \sigma, the z-score of a value X is given by:

Z = \frac{X - \mu}{\sigma}

The zscore represents how many standard deviations the value of X is above or below the mean \mu. This means that the baby with the lowest Zscore is the one who weighs relatively less to the gestation period.

33 week gestation period baby:

Babies born after a gestation period of 32 to 35 weeks have a mean weight of 2700 grams and a standard deviation of 900 grams, so \mu = 2700, \sigma = 900.

A 33​-week gestation period baby weighs 2275 grams. So X = 2275.

Z = \frac{X - \mu}{\sigma}

Z = \frac{2275 - 2700}{900}

Z = -0.47

41 week gestation period baby:

Babies born after a gestation period of 40 weeks have a mean weight of 3200 grams and a standard deviation of 450 grams, so \mu = 3200, \sigma = 450

A 41​-week gestation period baby weighs 2775 ​grams, so X = 2775.

Z = \frac{X - \mu}{\sigma}

Z = \frac{2775 - 3200}{450}

Z = -0.94

The 41 week gestation period baby weighs less relative to the gestation period, since he has a lower zscore.

8 0
3 years ago
elsa and liz thought they could fix dinner in 45 minutes ,when they were halfway done, 0.4 of an hour had passed,did they fix di
ipn [44]
No, they fixed dinner in about 48 minutes.

8 0
3 years ago
Read 2 more answers
HELP PLEASE
Anuta_ua [19.1K]

Answer:

The Drama Club needs to sell more than 3 pictures to make a profit.

The inequality 10x ≥ 2.55x +25  represents the situation.

Step-by-step explanation:

Given that:

Rent for lighting equipment = $25

Price per print = $2.55

Selling price of one picture = $10

x be the number of pictures.

Selling price * No. of pictures sold ≥ Price of per print * pictures printed + rent

10x ≥ 2.55x +25

10x-2.55x≥25

7.45x≥25

Dividing both sides by 7.45

\frac{7.45x}{7.45}\geq \frac{25}{7.45}\\x\geq 3.35

Hence,

The Drama Club needs to sell more than 3 pictures to make a profit.

The inequality 10x ≥ 2.55x +25  represents the situation.

5 0
3 years ago
On the day she was born, a baby leopard had 9 spots. Each day 4 more appeared. After 5 days, how many spots did the baby leopard
kherson [118]
The baby leopard would have no more spots because 4×5=20 and if the leopard had 9 spots at the start and over the course of five days it lost 20 spots, it would be -11 spots left.
7 0
4 years ago
Read 2 more answers
Factor the trinomial below. Picture is attached.
puteri [66]
(x-4)(x+6)
x= 4, -6
...........
8 0
4 years ago
Read 2 more answers
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