Explanation:
weight of water displaced=weight of sphere,
Since, plastic sphere floats in water with 50.0% of its volume submerged
so, water=2 sphere,
so sphere's density = 1/2 of water's density
Now, weight of glycerin displaced=weight of sphere,
Also given This same sphere floats in glycerin with 40.0% of its volume submerged.
so glycerin =2.5 sphere,
so sphere's density = .4 of glycerin's = 1/2 of water's.
So glycerin = 1.25 water
Answer:
456
Explanation:
impulse = Force x (time of contact)
this isn't really much information but hope this helps !: )
Answer:
8m * (μg/v)^2
Explanation:
k, the spring constant = ?
(k in terms of μ, m, g, and v.)
Frictional force = μmg
Note: lost KE is converted to work done against the friction + PE of the spring
1/2mv2 = μmgx + 1/2kx^2....equation i
Cancel the 1/2 on both sides
mv^2 = μmgx + kx^2
Lets recall that:
Due to frictional effect, further enegy will be lost when the spring recoils backward
Therefore
1/2kx^2 = μmgx..... equation ii
Let's substitute 1/2kx^2 in equation I for ii
So we can say that:
1/2mv^2 = (μmgx)+ μmgx
1/2mv^2 = 2 (μmgx)
1/4mv^2 = μmgx
Cancel out m on both sides
1/4v^2 = μgx
Make x subject of the formula
x = (1/4v^2) / (μg)...... equation iii
substitute x to equation ii
But first make k in equation ii subject of the formula
1/2kx^2 = μmgx
k = 2μmg/x
Now substitute x
k = 2μmg / ((1/4v^2) / (μg))
k = 2μmg * ((μg) / (1/4v^2))
k = 8m * (μg/v)^2
8m * (μg/v)^2
Answer: Choice B
There are triple bonds between the carbon (C) and oxygen (O) atoms. Then there are 2 dots on either side
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Explanation:
When it comes to interaction and chemistry, all that matters is the valence shell or valence electrons. This is the outermost shell. This is because various elements do not interact with the inner electrons (they're locked in place so to speak and don't move to other elements).
Carbon has 6 protons, which is what uniquely makes up this element. This means there are 6 electrons. The inner shell has 2 electrons and the valence shell has 4 electrons. Two electrons are shown as the two blue dots on the left side of the C. The other two electrons form two of the lines, or the bonds, between the C and O.
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Oxygen has 8 protons and 8 electrons. It has 2 electrons in the inner shell and 6 electrons in the valence shell. Two of those electrons are the red dots on the right side of the O. The other 4 electrons are shared to form the bonds with the carbon atom.
This is where things get a bit tricky. I've shown a diagram below indicating that one of the oxygen electrons (red dot) is passed to the carbon, as this carbon atom is pulling on the oxygen electron. But the oxygen atom is pulling on it as well, which forms one of the triple bonds.
So this is why diagram B is the final answer. This is something you can logically determine (remembering the rules of how each electron shell is formed), or it's something you'll need to memorize. In the real world, it's easy to forget a lot of info like this, so that's why having it handy as a lookup reference is preferable.