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2 years ago

Drag the tiles to the correct boxes to complete the pairs.

Physics

1 answer:

Brut [27]2 years ago

3 0

Answer:

5 percent = normal matter

68 percent = dark energy

27 percent = dark matter

Explanation:

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Science Virtual Lab: Smithsonian Museum Of Natural History

Viefleur [7K]

Your answers are correct. You have to read the plaques in the virtual lab to find the answers. So it shows you read them.

1. billion

2. modern

3. Organism

4. Heights

5. clams

6. flowery

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3 years ago

Influenced by the gravitational pull of a distant star, the velocity of an asteroid changes from from +19.3 km/s to −18.8 km/s o

muminat

As per above given data

initial velocity = 19.3 km/s

final velocity = - 18.8 km/s

now in order to find the change in velocity

$\Delta v = v_f - v_i$

$\Delta v = -18.8 - 19.3$

$\Delta v = -38.1 km/s$

$\Delta v = -3.81 * 10^4 m/s$

Part b)

Now we need to find acceleration

acceleration is given by formula

$a = \frac{\Delta v}{\Delta t}$

given that

$\Delta v =- 3.81 * 10^4 m/s$

$\Delta t = 2.07 years = 6.53 * 10^7 s$

now the acceleration is given as

$a = \frac{-3.81 * 10^4}{6.53 * 10^7}$

$a = - 5.84 * 10^{-4}m/s^2$

so above is the acceleration

4 0

3 years ago

A vacuum cleaner has a rating of 460 W on 230 V mains. The value of the fuse connected in the plug will be

amid [387]

Answer:

2 amps

Explanation:

Given data

Power = 460W

voltage= 230V

Required

The amperage/ current of the fuse

Recall P= IV

I= P/V

I= 460/230

I=2 amps

Hence the current of the fuse is 2 amps

7 0

3 years ago

What kind of relationship does a human have with the bacteria that lives in her/his digestive tract?

Misha Larkins [42]

The one that both benefits each other is the one I think it's mutalistic

4 0

3 years ago

Two positive charges of 6 µC are separated by a distance of 50 cm in air. What is the electric field strength at the midpoint of

attashe74 [19]

Answer:

The electric field strength at the midpoint of the line joining the charges is zero (0)

Explanation:

Given that the two charges are both positive (same charge) and are equal in magnitude that is 6uC. The electric field strength at the midpoint of the line joining the two charges will be equal and opposite in magnitude, therefore they will cancel each other out and the electric field strength at this point will be equal to zero.

4 0

3 years ago