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Brilliant_brown [7]
3 years ago
6

What is a cell GJFFVf xfhdfvcdd

Chemistry
2 answers:
andreev551 [17]3 years ago
6 0

Answer:

Yeah

Explanation:

balu736 [363]3 years ago
5 0
In biology, the smallest unit that can live on its own and that makes up all living organisms and the tissues of the body’s a cell. A cell has three main parts: the cell membrane, the nucleus, and the cytoplasm. ... The nucleus is a structure inside the cell that contains the nucleolus and most of the cell's DNA.

Hope that helps
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This is the picture answer this plsss..
Ulleksa [173]

Answer:

he is a weelder because of him taking a peice of metal and recreateing it.

Explanation:

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QUICKEST GETS BRAINLIEST AND 7 POINTS
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A positive solid sphere with electrons dispersed.
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3 years ago
In two or more complete sentences explain how to balance the chemical equation and classify its reaction type.
Artemon [7]
<h3>Answer:</h3>

#1. Balanced equation: 2C₅H₅ + Fe → Fe(C₅H₅)₂

#2. Type of reaction: Synthesis reaction

<h3>Explanation:</h3>
  • Balanced equations are equations that obey the law of conservation of mass.
  • When an equation is balanced the number of atoms of each element is equal on both side of the equation.
  • Equations are balanced by putting appropriate coefficients on the reactants and products.
  • In our case, we are going to put coefficients 2, 1 and 1.
  • Thus, the balanced equation will be;

2C₅H₅ + Fe → Fe(C₅H₅)₂

  • This type of a reaction is known as synthesis reaction, in which two or more reactants or compounds combine to form a single compound or product.
8 0
3 years ago
1. What elements are carbohydrates generally composed of?
Llana [10]
The correct answer is  hydrogen<span>, and </span>oxygen<span>. </span>
4 0
3 years ago
Read 2 more answers
The ksp of yttrium fluoride, yf3, is 8.62 × 10-21. calculate the molar solubility of this compound.
motikmotik

Answer:

The molar solubility of YF₃ is 4.23 × 10⁻⁶ M.

Explanation:

In order to calculate the molar solubility of YF₃ we will use an ICE chart. We identify 3 stages: Initial, Change and Equilibrium and we complete each row with the concentration of change of concentration. Let's consider the solubilization of YF₃.

       YF₃(s) ⇄ Y³⁺(aq) + 3 F⁻(aq)

I                       0               0

C                     +S            +3S

E                       S              3S

The solubility product (Ksp) is:

Ksp = [Y³⁺].[F⁻]³= S . (3S)³ = 27 S⁴

S=\sqrt[4]{Ksp/27} =\sqrt[4]{8.62 \times 10^{-21}  /27}=4.23 \times 10^{-6}M

6 0
3 years ago
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