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3 years ago

What were Katherine Johnson publications?

1 answer:

7 0

Answer: 1 Reaching for the Moon : the autobiography of NASA mathematician Katherine 2 Johnson by Katherine G Johnson( Book )

3 Katherine Johnson by Thea Feldman( Book )

4 Katherine Johnson by Ebony Wilkins( Book )

5Counting the stars by Lesa Cline-Ransome( Book )

6An Act to Award Congressional Gold Medals to Katherine Johnson and Dr.

Explanation:

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Between a plate and the body of a bolt, the projected area is equal to the product of the bolt _______ and the plate _______.

Elan Coil [88]

Answer:

Projected area= Diameter of the bolt* thickness.

Explanation:

Between a plate and the body of a bolt, the projected area is equal to the product of the bolt _Diameter of the bolt______ and the plate ___thickness____.

Projected area= Diameter of the bolt* thickness.

Projected area is a 2-dimensional area measurement of a 3-dimensional body by projecting its surface on an arbitrary plane

8 0

3 years ago

The apparent height of a building 10.5 km away is 0.02 radians. What is the approximate height of the building to the nearest me

Ksenya-84 [330]

Answer:

Approximate height of the building is 23213 meters.

Explanation:

Let the height of the building be represented by h.

0.02 radians = 0.02 × $\frac{180^{o} }{\pi }$

= 0.02 x (180/ $\frac{22}{7}$ )

0.02 radians = 1.146°

10.5 km = 10500 m

Applying the trigonometric function, we have;

Tan θ = $\frac{opposite}{adjacent}$

So that,

Tan 1.146° = $\frac{h}{10500}$

⇒ h = Tan 1.146° x 10500

= 2.21074 x 10500

= 23212.77

h = 23213 m

The approximate height of the building is 23213 m.

8 0

3 years ago

The rate at which an object moves is the object's __________.

11111nata11111 [884]

Answer:

speed

Explanation:

4 0

4 years ago

Read 2 more answers

The Doppler effect suggests that sound waves are relative to the observer. You know if an object is coming or going from the sou

mrs_skeptik [129]

A. Form the Brightness of the light

5 0

4 years ago

Read 2 more answers

You are trying to overhear a juicy conversation, but from your distance of 24.0m , it sounds like only an average whisper of 40.

Neporo4naja [7]

Answer:

The distance is $r_2 = 0.24 \ m$

Explanation:

From the question we are told that

The distance from the conversation is $r_1 = 24.0 \ m$

The intensity of the sound at your position is $\beta _1 = 40 dB$

The intensity at the sound at the new position is $\beta_2 = 80.0dB$

Generally the intensity in decibel is is mathematically represented as

$\beta = 10dB log_{10}[\frac{d}{d_o} ]$

The intensity is also mathematically represented as

$d = \frac{P}{A}$

$\beta = 10dB * log_{10}[\frac{P}{A* d_o} ]$

=> $\frac{\beta}{10} = log_{10} [\frac{P}{A (l_o)} ]$

From the logarithm definition

=> $\frac{P}{A * d_o} = 10^{\frac{\beta}{10} }$

=> $P = A (d_o ) [10^{\frac{\beta }{ 10} } ]$

Here P is the power of the sound wave

and A is the cross-sectional area of the sound wave which is generally in spherical form

Now the power of the sound wave at the first position is mathematically represented as

$P_1 = A_1 (d_o ) [10^{\frac{\beta_1 }{ 10} } ]$

Now the power of the sound wave at the second position is mathematically represented as

$P_2 = A_2 (d_o ) [10^{\frac{\beta_2 }{ 10} } ]$

Generally power of the wave is constant at both positions so

$A_1 (d_o ) [10^{\frac{\beta_1 }{ 10} } ] = A_2 (d_o ) [10^{\frac{\beta_2 }{ 10} } ]$

$4 \pi r_1 ^2 [10^{\frac{\beta_1 }{ 10} } ] = 4 \pi r_2 ^2 [10^{\frac{\beta_2 }{ 10} } ]$

$r_2 = \sqrt{r_1 ^2 [\frac{10^{\frac{\beta_1}{10} }}{ 10^{\frac{\beta_2}{10} }} ]}$

substituting value

$r_2 = \sqrt{ 24^2 [\frac{10^{\frac{ 40}{10} }}{10^{\frac{80}{10} }} ]}$

$r_2 = 0.24 \ m$

7 0

3 years ago