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igomit [66]
3 years ago
12

Suppose that there is an air sample and a water sample, each of the same mass and each with an initial temperature, Tinitial, of

0° C. Now, imagine that both the air and water are heated using sunlight. If the same total amount of energy is added to both samples, which sample will reach a higher temperature, Tfinal? The air or the water?
Chemistry
2 answers:
Svetlanka [38]3 years ago
7 0

Answer:

The air will reach a higher final temperature because its specific heat is lower.

Explanation: right from PLATO so paraphrase a lil bit

klasskru [66]3 years ago
6 0

Answer:

The air will reach a higher final temperature because its specific heat is lower.

Explanation:

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stira [4]

Answer:

b, decrease in movement of the molecules

Explanation:

removing the energy will begin making the molecules lock up and stop moving due to the loss of energy.

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4 0
3 years ago
Vanillin (used to flavor vanilla ice cream and other foods) is the substance whose aroma the human nose detects in the smallest
balu736 [363]

Answer:

Cost to supply enough vanillin is 3.2\$

Explanation:

Threshold limit of vanillin in air is 2.0\times 10^{-11}g per litre means there should be 2.0\times 10^{-11}g of vanillin in 1L of air to detect aroma of vanillin.

1ft^{3}=28.32L

So, 5.0\times 10^{7}ft^{3}=(5.0\times 10^{7}\times 28.32)L

So amount of vanillin should be present to detect = (2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)g

As cost of 50 g vanillin is 112\$ therefore cost of  (2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)gvanillin = (2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32\times 112)\$ = 3.2\$

5 0
3 years ago
A 5.024 mg sample of an unknown organic molecule containing carbon, hydrogen, and nitrogen only was burned and yielded 13.90 mg
Dafna1 [17]

Answer:

C8H17N

Explanation:

Mass of the unknown compound = 5.024 mg

Mass of CO2 = 13.90 mg

Mass of H2O = 6.048 mg

Next, we shall determine the mass of carbon, hydrogen and nitrogen present in the compound. This is illustrated below:

For carbon, C:

Molar mass of CO2 = 12 + (2x16) = 44g/mol

Mass of C = 12/44 x 13.90 = 3.791 mg

For hydrogen, H:

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H = 2/18 x 6.048 = 0.672 mg

For nitrogen, N:

Mass N = mass of unknown – (mass of C + mass of H)

Mass of N = 5.024 – (3.791 + 0.672)

Mass of N = 0.561 mg

Now, we can obtain the empirical formula for the compound as follow:

C = 3.791 mg

H = 0.672 mg

N = 0.561 mg

Divide each by their molar mass

C = 3.791 / 12 = 0.316

H = 0.672 / 1 = 0.672

N = 0.561 / 14 = 0.040

Divide by the smallest

C = 0.316 / 0.04 = 8

H = 0.672 / 0.04 = 17

N = 0.040 / 0.04 = 1

Therefore, the empirical formula for the compound is C8H17N

8 0
3 years ago
16. These conditions occur over the course of a day. Cumulus clouds appear and create rain showers. The sky clears soon after th
olya-2409 [2.1K]

Answer:

A

Explanation:

I believe it's A gggggg%gggggtggg

6 0
3 years ago
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