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hjlf
2 years ago
14

Typical noise associated with failed cv joint​

Engineering
1 answer:
igor_vitrenko [27]2 years ago
3 0

Answer:

A worn inner CV joint often makes a clunking noise during starts and stops.

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A three-phase, 480 Volt, 120 horsepower, 50 Hertz four-pole induction motor delivers rated output power at a slip of 4%. Determi
kkurt [141]

Answer:

a) n_{s} = 750\,rpm, b) n_{r} = 720\,rpm, c) n_{p} = 30\,rpm

Explanation:

a) Synchronous speed is:

n_{s} = f\cdot \frac{60}{n_{poles}}

n_{s} = (50\,hz)\cdot \left(\frac{60}{4}\right)

n_{s} = 750\,rpm

b) Actual motor speed is:

S = \frac{n_{s}-n_{r}}{n_{s}} \times 100\%

n_{r} = \left(1-\frac{S}{100}\right)\cdot n_{s}

n_{r} = \left( 1 - \frac{4}{100}  \right)\cdot 750\,rpm

n_{r} = 720\,rpm

c) Slip speed is:

n_{p} = n_{s} - n_{r}

n_{p} = 750\,rpm - 720\,rpm

n_{p} = 30\,rpm

4 0
3 years ago
Read 2 more answers
The first step of the Engineering Design Process is to select the
Dvinal [7]

Answer:

I think it's false

Explanation:

the first step is to figure out the needs and constraints

4 0
3 years ago
one number is 11 more than another number. find the two number if three times the larger number exceeds four times the smaller n
vaieri [72.5K]

Answer:

a = 40

b = 29

Explanation:

Give a place holder for the numbers that we don't know.

Lets call the two numbers a and b.

From the given info, we can write an expression and solve it:

"one number is 11 more than another number"

a = 11 + b

from this, we know that a > b.

''three times the larger number exceeds four times the smaller number by 4"

3a = 4b + 4

Now we have 2 equations, we can use them to solve using whatever method you want.

a = 11 + b

3a = 4b + 4

I will be using matrices RREF to solve for this.

a - b = 11

3a - 4b = 4

\begin{bmatrix}1 & -1  & 11\\3 & -4 & 4 \end{bmatrix}

\begin{bmatrix}1 & 0  & 40\\0 & 1 & 29 \end{bmatrix}

a = 40

b = 29

6 0
3 years ago
A 10-mm steel drill rod was heat-treated and ground. The measured hardness was found to be 290 Brinell. Estimate the endurance s
grandymaker [24]

Answer:

the endurance strength  S_e = 421.24  MPa

Explanation:

From the given information; The objective is to estimate the endurance strength, Se, in MPa .

To do that; let's for see the expression that shows the relationship between the ultimate tensile strength and Brinell hardness number .

It is expressed as:

200 \leq H_B \leq 450

S_{ut} = 3.41 H_B

where;

H_B = Brinell hardness number

S_{ut} =  Ultimate tensile strength

From ;

S_{ut} = 3.41 H_B; replace 290 for H_B ; we have

S_{ut} = 3.41 (290)

S_{ut} = 988.9 MPa

We can see that the derived value for the ultimate tensile strength when the Brinell harness number = 290 is less than 1400 MPa ( i.e it is 988.9 MPa)

So; we can say

S_{ut} < 1400

The Endurance limit can be represented by the formula:

S_e ' = 0.5 S_{ut}

S_e ' = 0.5 (988.9)

S_e ' = 494.45 MPa

Using Table 6.2 for parameter for Marin Surface modification factor. The value for a and b are derived; which are :

a = 1.58

b =  -0.085

The value of the surface factor can be calculate by using the equation

k_a = aS^b_{ut}

K_a = 1.58 (988.9)^{-0.085

K_a = 0.8792

The formula that is used to determine the value of  k_b for the rotating shaft of size factor d = 10 mm is as follows:

k_b = 1.24d^{-0.107}

k_b = 1.24(10)^{-0.107}

k_b = 0.969

Finally; the the endurance strength, Se, in MPa if the rod is used in rotating bending is determined by using the expression;

S_e =k_ak_b S' _e

S_e= 0.8792×0.969×494.45

S_e = 421.24  MPa

Thus; the endurance strength  S_e = 421.24  MPa

8 0
3 years ago
A sports car has a drag coefficient of 0.29 and a frontal area of 20 ft2, and is travelling at a speed of 120 mi/hour. How much
Andrej [43]

Answer:

Power required to overcome aerodynamic drag is 50.971 KW

Explanation:

For explanation see the picture attached

4 0
3 years ago
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