Answer:
16∠45° Ω
Explanation:
Applying,
Z = V/I................... Equation 1
Where Z = Impedance, V = Voltage output, I = current input.
Given: V = 120cos(10t+75°), = 120∠75°, I = 7.5cos(10t+30) = 7.5∠30°
Substitute these values into equation 1
Z = 120cos(10t+75°)/7.5cos(10t+30)
Z = 120∠75°/ 7.5∠30°
Z = 16∠(75°-30)
Z = 16∠45° Ω
Hence the impedance of the linear network is 16∠45° Ω
The work done on the backpack by the student applies 80 N of force to lift the backpack 1.5 m is 120J.
<h3>How to calculate work done?</h3>
Work done is a measure of energy expended in moving an object; most commonly, force times distance.
It is said that no work is done if the object does not move, hence, the work done on an object can be calculated as follows:
Work done = Force × Distance
According to this question, a student carries a very heavy backpack and to lift the backpack off the ground, the student must apply 80 N of force to lift the backpack 1.5 m.
Work done = 80N × 1.5m
Work done = 120J
Therefore, the work done on the backpack by the student applies 80 N of force to lift the backpack 1.5 m is 120J.
Learn more about work done at: brainly.com/question/28172139
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1 ys is the smallest unit of time.
The factors which are affected will be based on the distance or range between the charged objects A and B
<u>Explanation:</u>
<u>Definition:</u>
- The force, F among the two-point size charges A and B are divided by a range r is given by Coulomb formula.
F=9x10^9 AB/r²
<u>Factors:</u>
- If the range among them is doubled the force will be decreased to 1/4 of the initial value. And if the range is split, the force will be four times.
- If the range among them is tripled, the force will be decreased to 1/9 of the initial value. If the range is decreased to one-third of the new value, the force will rise to Nine times the initial value.
