If the impulse is 25 N-s, then so is the change in momentum.
The mass of the ball is extra, unneeded information.

Just to make sure, we can check out the units:

Momentum = (mass) x (speed) = kg-meter / sec

Impulse = (force) x (time) = (kg-meter / sec²) x (sec) = kg-meter / sec

3 0

4 years ago

Read 2 more answers

Oak trees make many acorns that can become new oak trees what is this an example of

Kisachek [45]

Reproduction! hope this helps u.

4 0

4 years ago

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A solenoid 1.39 m long and 3.20 cm in diameter carries a current of 17.1 A. The magnetic field inside the solenoid is 26.9 mT. F

Mariulka [41]

Explanation:

It is given that,

Length of the solenoid, l = 1.39 m

Diameter of the solenoid, d = 3.2 cm = 0.032 m

Radius of solenoid, r = 0.016 m

Magnetic field inside the solenoid, $B=26.9\ mT=26.9\times 10^{-3}\ T$

We need to find the length of the wire forming the solenoid. The magnetic field inside the solenoid is given by :

$B=\mu_o nI$

n is number of turns per unit length

$B=\dfrac{\mu_o NI}{l}$

$N=\dfrac{Bl}{\mu_o I}$

$N=\dfrac{26.9\times 10^{-3}\times 1.39}{4\pi \times 10^{-7}\times 17.1}$

N = 1740.04

The total length having N loop is,

$L=2\pi r\times N$

$L=2\pi \times 0.016\times \times 1740.04$

L = 174.92 m

So, the length of the wire forming the solenoid is 174.92 meters. Hence, this is the required solution.

7 0

4 years ago

Two identical conducting spheres each having a radius of 0.500 cm are connected by a light, 1.90-m-long conducting wire. A charg

Ivan

Answer: 4.19 N

Explanation: In order to determinate the tension applied on the wire we have to calculate the electric force between the conductor spheres connected by the wire.

As the wire is a conductor the spheres are at same potential so we have:

V1=V2

V1=k*Q1/r1 and V2=k*Q2/r2

where r1=r2, then

Q1=Q2

so the electric force is given by:

F=k*Q^2/d^2 where d is the distance between the spheres.

Finally replacing the values, we have

F=9*10^9(41*10^-6)^2/(1.9)^2= 4.19 N

8 0

3 years ago