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IceJOKER [234]
3 years ago
14

Light waves are: O Transverse waves O Longitudinal Waves

Physics
2 answers:
Tanya [424]3 years ago
7 0

Answer: Transverse waves

Olenka [21]3 years ago
3 0

Answer:

They are Transverse Waves.

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A proton is released in a uniform electric field, and it experiences an electric force of 5 X 10^-10 N toward the South. What is
Ymorist [56]

Answer:

Electric field on proton

E=3.12\times 10^9\ N/C

Explanation:

Given that

Force,F=5\times 10^{-10}\ N

We know that

Charge on proton

q=1.6\times 10^{-19}\ C

We know that

Force = Electric field x Charge

F= E x q

E=\dfrac{F}{q}\ N/C

E=\dfrac{5\times 10^{-10}}{1.6\times 10^{-19}}\ N/C

E=3.12\times 10^9\ N/C

Electric field on proton

E=3.12\times 10^9\ N/C

4 0
3 years ago
A 0.5 m diameter wagon wheel consists of a thin rim having a mass of 7 kg and six spokes, each with a mass of 1.2 kg. 1.2 kg 7 k
Arte-miy333 [17]

Explanation:

It is given that,

Mass of the rim of wheel, m₁ = 7 kg

Mass of one spoke, m₂ = 1.2 kg

Diameter of the wagon, d = 0.5 m

Radius of the wagon, r = 0.25 m

Let I is the the moment of inertia of the wagon wheel for rotation about its axis.

We know that the moment of inertia of the ring is given by :

I_1=m_1r^2

I_1=7\times (0.25)^2=0.437\ kgm^2

The moment of inertia of the rod about one end is given by :

I_2=\dfrac{m_2l^2}{3}

l = r

I_2=\dfrac{m_2r^2}{3}

I_2=\dfrac{1.2\times (0.25)^2}{3}=0.025\ kgm^2

For 6 spokes, I_2=0.025\times 6=0.15\ kgm^2

So, the net moment of inertia of the wagon is :

I=I_1+I_2

I=0.437+0.15=0.587\ kgm^2

So, the moment of inertia of the wagon wheel for rotation about its axis is 0.587\ kgm^2. Hence, this is the required solution.

4 0
4 years ago
Pls help i’ll give brainliest if you give a correct answer!!
arsen [322]

Answer:

C. The distance traveled by an object at a certain velocity.

Explanation:

YW!

3 0
3 years ago
Read 2 more answers
You are performing a double slit experiment very similar to the one from DL by shining a laser on two nattow slits spaced 7.5 x
Blizzard [7]

Complete Question

You are performing a double slit experiment very similar to the one from DL by shining a laser on two nattow slits spaced 7.5 * 10^{-3} meters apart. However, by placing a piece of crystal in one of the slits, you are able to make it so that the rays of light that travel through the two slits are Ï out of phase with each other (that is to say, Ao,- ). If you observe that on a screen placed 4 meters from the two slits that the distance between the bright spot closest to center of the pattern is 1.5 cm, what is the wavelength of the laser?

Answer:

The  wavelength is  \lambda  =  56250 nm

Explanation:

From the question we are told that

   The  distance of slit separation is  d =  7.5 *10^{-3} \  m

   The  distance of the screen is  D =  4 \  m

    The  distance between the bright spot closest to the center of the interference  is  k   = 1.5 \ cm = 0.015 \  m

   

Generally the width of the central  maximum fringe produced is mathematically represented as

        y  =  2 *  k  = \frac{ D  *  \lambda}{d}

  =>    2 *  0.015 =  \frac{ \lambda  *  4}{ 7.5 *10^{-3}}

   =>   \lambda  =  56250 *10^{-9} \ m

=>      \lambda  =  56250 nm

7 0
3 years ago
A student drops an egg from the roof of their house onto a trampoline. The egg feels a change in momentum of 2.2 kg^ * m/s in 1.
geniusboy [140]

Answer:

F = m a = m v / t       where v is the change in velocity in time t

F = p / t       since m v is equal to p

F = 2.2 (kg m / s) / 1.1 s = 2 kg-m / s^2 = 2 N

Or you can use the impulse equation

8 0
2 years ago
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