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IceJOKER [234]
3 years ago
14

Light waves are: O Transverse waves O Longitudinal Waves

Physics
2 answers:
Tanya [424]3 years ago
7 0

Answer: Transverse waves

Olenka [21]3 years ago
3 0

Answer:

They are Transverse Waves.

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Two identical balls collide one was initially at rest. after the collision one of the balls has a velocity of 3 m/s south. the o
Butoxors [25]
Two identical balls collide<span> head on. The </span>initial velocity<span> of </span>one<span> is 0.75 </span>m/s<span> east, while that of the </span>other one<span> is 0.43 </span>m/s west<span>.</span>
4 0
3 years ago
PLEASE HELP AND HURRY
likoan [24]

Answer:

C

Explanation:

C. 12.8km

6 0
3 years ago
How do two sublevels of the same principal energy level differ from each other
Colt1911 [192]

Each energy sublevel corresponds to an orbital of a different shape.

Explanation:

Two sublevels of the same principal energy level differs from each other if the sublevels corrresponds to an orbital of a different shape.

  • The principal quantum number of an atom represents the main energy level in which the orbital is located or the distance of an orbital from the nucleus. It takes values of n = 1,2,3,4 et.c
  • The secondary quantum number gives the shape of the orbitals in subshells accommodating electrons.
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Take for example, Carbon:

                      1s² 2s² 2p²

   The second energy level is 2 but with two different sublevels of s and p. They have different shapes. S is spherical and P is dumb-bell shaped .

Learn more:

Quantum number brainly.com/question/9288609

#learnwithBrainly

7 0
3 years ago
A 0.50 kg toy is attached to the end of a 1.0 m very light string. The toy is whirled in a horizontal circular path on a frictio
xenn [34]

Answer:

The maximum speed will be 26.475 m/sec

Explanation:

We have given mass of the toy m = 0.50 kg

radius of the light string r = 1 m

Tension on the string T = 350 N

We have to find the maximum speed without breaking the string  

For without breaking the string tension must be equal to the centripetal force

So T=\frac{mv^2}{r}

So 350=\frac{0.5\times v^2}{1}

v^2=700

v = 26.475 m /sec

So the maximum speed will be 26.475 m/sec

6 0
3 years ago
How is the acceleration of an object in uniform circular motion constant?
nevsk [136]
In both magnitude and direction since acceleration is a vector quantity
5 0
3 years ago
Read 2 more answers
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