Answer:
The required mass of ice is 12.5 kg.
Explanation:
Mass of hot tea, = 1.8 kg
Initial temperature of hot tea = 80°C = 353 K
Initial temperature of ice = 0.00°C = 273 K
Final temperature of mixture = 10°C = 283 K
Heat of fusion of ice, L = 334 kJ/kg
Specific heat capacity of tea, = Specific heat capacity of water = 4190 J/kg/K
Heat lost tea = Heat gained by ice
Δ = L + Δ
Δ = (L + Δ)
1.8 x 4190 x (353 - 283) = (334 + (4190 x (283 - 2730))
1.8 x 4190 x 70 = (334 + (4190 x 10))
527940 = 42234
=
= 12.5004
= 12.5 kg
The required mass of ice is 12.5 kg.
Answer:
ωf = 4.53 rad/s
Explanation:
By conservation of the angular momentum:
Ib*ωb = (Ib + Ic)*ωf
Where
Ib is the inertia of the ball
ωb is the initial angular velocity of the ball
Ic is the inertia of the catcher
ωf is the final angular velocity of the system
We need to calculate first Ib, Ic, ωb:
ωb = Vb / (L/2) = 16 / (1.2/2) = 26.67 m/s
Now, ωf will be:
Answer:
Here are the em radiation in order of increasing frequency from left to right. Also, the wavelength decreases as we move from left to right.
Radio, micro, infrared, visible, ultraviolet, x-ray and gamma ray.
According to quantum physics, you use E = hf ( where E = energy of a photon of a type of em wave, h is Planck constant and f is frequency of that photon ) to find the energy.
From here you can see that as we move from left to right, energy increases because frequency increases.
Explanation:
Answer:
6.54 x 10^-10 N/kg
Explanation:
mass of the shell, M = 135 kg
radius of shell, R = 1.49 m
distance from the centre of the shell, r = 3.71 m
The gravitational filed is given by
E = 6.54 x 10^-10 N/kg
Thus, the gravitational field intensity at a distance 3.71 m is 6.54 x 10^-10 N/kg.
A resultante das duas forças será zero, já q os sentidos são opostos e sãos iguais em módulo, elas se anulam. Logo, se a força resultante é zero, e F=ma, aceleração também será igual a zero.